CODEWITHSUNDEEP
pythonlistsortingdictionary
Adhy Karina
Adhy Karina

Reputation: 63

Sorting a list with elements containing dictionary values

I'm trying to make a sorting system with card ranks and their values are obtained from a separate dictionary. In a simple deck of 52 cards, we have 2 to Ace ranks, in this case I want a ranking system where 0 is 10, J is 11, Q is 12, K is 13, A is 14 and 2 is 15 where 2 is the largest valued rank. The thing is, if there is a list where I want to sort rank cards in ASCENDING order according to the numbering system, how do I do so?

For example, here is a list, [3,5,9,7,J,K,2,0], I want to sort the list into [3,5,7,9,0,J,K,2]. I also made a dictionary for the numbering system as {'A': 14, 'K': 13, 'J': 11, 'Q': 12, '0': 10, '2': 15}.

THANKS

Upvotes: 3

Views: 204

Answers (2)

Schuh
Schuh

Reputation: 1095

This answer works:

    sorted(list_for_sorting, key=dictionary_you_wrote.__getitem__)

This does too:

    sorted_list = sorted(unsorted_list, key = lambda k: your_dictionary[k])

The sorted function uses each entry in the first argument (the object you want to sort), to call the second argument. That way the lamda function returns the value for the given item from the dictionary and sorted can use it as the key.

If any list entry is not in your_dictionary.keys(), this will not work. Either complete the dictionary or use

    sorted(unsorted_list, key = lambda k: your_dictionary[k] if k in your_dictionary.keys() else k)

Upvotes: 1

Ronald
Ronald

Reputation: 325

have you already tried

sorted(list_for_sorting, key=dictionary_you_wrote.__getitem__)

?

Upvotes: 0

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