CODEWITHSUNDEEP
javagraphjgrapht
iremce
iremce

Reputation: 620

JGraphT - UndirectedGraph - addEdge method does not work

I have a problem about UndirectedGraph usage. My code :

UndirectedGraph<String, DefaultEdge> graph =
            new SimpleGraph<String, DefaultEdge>(DefaultEdge.class);

 String v1 = "v1";
 String v2 = "v2";
 String v3 = "v3";
 String v4 = "v4";

 graph.addVertex(v1);
 graph.addVertex(v2);
 graph.addVertex(v3);
 graph.addVertex(v4);

 graph.addEdge(v1, v2);
 graph.addEdge(v2, v3);
 graph.addEdge(v3, v4);
 graph.addEdge(v4, v1);

Each vertex was added to graph successfully. Hovewer, addEdge method didn't work properly. When I debug this code, first addEdge line threw class not found exception.

I hope, you will help me. Thanks.

Upvotes: 0

Views: 2974

Answers (1)

andersoj
andersoj

Reputation: 22884

With jgrapht-0.8.3, the following works as expected:

import org.jgrapht.UndirectedGraph;
import org.jgrapht.graph.DefaultEdge;
import org.jgrapht.graph.SimpleGraph;

public class GraphTest {

  public static void main(String[] args) {
    UndirectedGraph<String, DefaultEdge> graph =
      new SimpleGraph<String, DefaultEdge>(DefaultEdge.class);

    String v1 = "v1";
    String v2 = "v2";
    String v3 = "v3";
    String v4 = "v4";

    graph.addVertex(v1);
    graph.addVertex(v2);
    graph.addVertex(v3);
    graph.addVertex(v4);

    graph.addEdge(v1, v2);
    graph.addEdge(v2, v3);
    graph.addEdge(v3, v4);
    graph.addEdge(v4, v1);
    
    if( graph.getEdge(v1, v2) != null) { System.out.println("SUCCESS"); }
    if (graph.getEdge(v2,v4) == null)  { System.out.println("SUCCESS"); }
  }
}

I get

SUCCESS

SUCCESS

Can you clarify what problem you're having?

Upvotes: 1

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