DannyF247
DannyF247

Reputation: 638

Java - Getting line from file

Below is my current function. It works fine and returns true if the lineToCompare is found.

public static int checkrank(String lineToCompare){
    try{
        // Open the file that is the first 
        // command line parameter
        FileInputStream fstream = new FileInputStream("ranks.txt");

        // Get the object of DataInputStream
        DataInputStream in = new DataInputStream(fstream);
        BufferedReader br = new BufferedReader(new InputStreamReader(in));

        String strLine;
        //Read File Line By Line

        while ((strLine = br.readLine()) != null)   {
        //Compare the line with the line to compare (string)
        if(strLine.trim().compareTo(lineToCompare) == 0)
          return true;
        }

        //Close the input stream
        in.close();
    }catch (Exception e){//Catch exception if any
        System.err.println("Error: " + e.getMessage());
    }

    return false;

}

However, I need it to get the line AFTER the lineToCompare is found.

Here's an example text file:

xXPwnageLolXx
1
SomethingTest
0
AnotherSomething
3

I need it to find the line of text (lineToCompare), then return the number AFTER the line found. How would I do this?

Upvotes: 2

Views: 572

Answers (1)

Amir Afghani
Amir Afghani

Reputation: 38541

while ((strLine = br.readLine()) != null)   {
    //Compare the line with the line to compare (string)
    if(strLine.trim().compareTo(lineToCompare) == 0) {
      //I found it!  Read the next line...
      final String lineAfter = br.readLine();
      return Integer.parseInt(lineAfter);    
    }
}

I've edited this snippet to include Dowards suggestion. The local variable is unnecessary, I'm just leaving it in for readability.

Upvotes: 5

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