Reputation: 7702
Suppose I have this array of hashes:
[
{"href"=>"https://company.campfirenow.com", "name"=>"Company", "id"=>123456789, "product"=>"campfire"},
{"href"=>"https://basecamp.com/123456789/api/v1", "name"=>"Company", "id"=>123456789, "product"=>"bcx"},
{"href"=>"https://company.highrisehq.com", "name"=>"Company", "id"=>123456789, "product"=>"highrise"}
]
How can I parse the "href" value of the hash where "product"=>"bcx"
Is there any easy way to do this in Ruby?
Upvotes: 27
Views: 34983
Reputation: 95308
ary = [
{"href"=>"https://company.campfirenow.com", "name"=>"Company", "id"=>123456789, "product"=>"campfire"},
{"href"=>"https://basecamp.com/123456789/api/v1", "name"=>"Company", "id"=>123456789, "product"=>"bcx"},
{"href"=>"https://company.highrisehq.com", "name"=>"Company", "id"=>123456789, "product"=>"highrise"}
]
p ary.find { |h| h['product'] == 'bcx' }['href']
# => "https://basecamp.com/123456789/api/v1"
Note that this only works if the element exists. Otherwise you will be calling the subscription operator []
on nil
, which will raise an exception, so you might want to check for that first:
if h = ary.find { |h| h['product'] == 'bcx' }
p h['href']
else
puts 'Not found!'
end
If you need to perform that operation multiple times, you should build yourself a data structure for faster lookup:
href_by_product = Hash[ary.map { |h| h.values_at('product', 'href') }]
p href_by_product['campfire'] # => "https://company.campfirenow.com"
p href_by_product['bcx'] # => "https://basecamp.com/123456789/api/v1"
Upvotes: 55