CODEWITHSUNDEEP
phptypes
user1393876
user1393876

Reputation: 53

PHP Type-Cast Confusion

I have the following code:

<?php
    $val = 0;
    $res = $val == 'true';

    var_dump($res);
?>

I always was under impression that $res should be 'false' as in the above expression PHP would try to type cast $val to boolean type (where zero will be converted as false) and a string (non-empty string is true). But if I execute the code above output will be:

boolean true

Am I missing something? Thanks.

Upvotes: 2

Views: 804

Answers (3)

Michael Berkowski
Michael Berkowski

Reputation: 270775

In PHP, all non-empty, non-numeric strings evaluate to zero, so 0 == 'true' is TRUE, but 0 === 'true' is FALSE. The string true has not been cast to a boolean value, but is being compared as a string to the zero. The zero is left as an int value, rather than cast as a boolean. So ultimately you get:

// string 'true' casts to int 0
0 == 0 // true

Try this:

echo intval('true');
// 0
echo intval('some arbitrary non-numeric string');
// 0

Review the PHP type comparisons table. In general, when doing boolean comparisons in PHP and types are not the same (int to string in this case), it is valuable to use strict comparisons.

Upvotes: 3

Suresh kumar
Suresh kumar

Reputation: 2102

Try this

<?php
    $val = 1;
    $res = (bool)$val == 'true';

    var_dump($res);
?>

Upvotes: 0

John Conde
John Conde

Reputation: 219924

Because $val is the first operator PHP converts the string true to an integer which becomes 0. As a result 0 ==0 and your result is true;

Upvotes: 0

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