Reputation: 5092
I'm making an Android Java program which is taking double values from the user. If I run the program on the computer, it works great because of the locale of my computer, EN_UK. But when I run it on my mobile phone with FI_FI locale, it won't work. I know the reason: In UK, people use dot as decimal separator but here in Finland, the decimal separator is comma.
DecimalFormat df = new DecimalFormat("#.#");
Double returnValue = Double.valueOf(df.format(doubleNumber));
When I'm using comma, it says java.lang.NumberFormatException: Invalid double: "1234,5"
.
How can I make it work with them both, comma and dot?
Upvotes: 19
Views: 44829
Reputation: 132
Me Error:
java.lang.NumberFormatException: Invalid float: "1,683.88"
... and this work for me
replace(",", "")
Upvotes: -1
Reputation: 1952
This should work for both Java(Tested) as well as android :)
Class Name: In18Helper.java
package com.akmeher.app.utils;
import java.text.NumberFormat;
import java.text.ParseException;
import java.util.Locale;
public class In18Helper {
private final static In18Helper mHelper = new In18Helper();
public static final In18Helper getInstance() {
return mHelper;
}
public double getDouble(String sValue, Locale locale) {
NumberFormat numberFormat = NumberFormat.getInstance(locale);
Number parse = null;
try {
parse = numberFormat.parse(sValue);
} catch (ParseException e) {
e.printStackTrace();
}
return parse == null ? 0 : parse.doubleValue();
}
}
Class Name: Application.java
package com.akmeher.app;
import java.util.Locale;
import com.akmeher.app.utils.In18Helper;
public class Application {
static DataModel[] testData = new DataModel[] {
new DataModel("1.034567", Locale.ENGLISH),
new DataModel("1,0345.67", Locale.ENGLISH),
new DataModel("1.0345,67", Locale.GERMANY),
new DataModel("1,034,567", Locale.CANADA),
new DataModel("1.034567", Locale.KOREA),
new DataModel("1,03.4567", Locale.ITALY) };
/**
* @param args
*/
public static void main(String[] args) {
for (int i = 0; i < testData.length; i++) {
double d = In18Helper.getInstance().getDouble(testData[i].mValue,
testData[i].mLocale);
System.out.println("Trial Value: "+testData[i].mValue+" for Locale: "+testData[i].mLocale+" converted to: "+d);
}
}
private static class DataModel {
String mValue;
Locale mLocale;
public DataModel(String value, Locale locale) {
this.mLocale = locale;
this.mValue = value;
}
}
}
Output:
Trial Value: 1.034567 for Locale: en converted to: 1.034567
Trial Value: 1,0345.67 for Locale: en converted to: 10345.67
Trial Value: 1.0345,67 for Locale: de_DE converted to: 10345.67
Trial Value: 1,034,567 for Locale: en_CA converted to: 1034567.0
Trial Value: 1.034567 for Locale: ko_KR converted to: 1.034567
Trial Value: 1,03.4567 for Locale: it_IT converted to: 1.03
Hope this will help somebody to make use of.
Upvotes: 2
Reputation: 1
Not a best way but worked for me;
Double val=null;
try{
val=Double.valueOf(value);
}catch(Exception e){
val=Double.valueOf(value.replace(',','.'));
}
Double val=null;
try{
val=Double.valueOf(value);
}catch(Exception e){
val=Double.valueOf(value.replace(',','.'));
}
return val;
Upvotes: -1
Reputation: 4801
public static Double parseDoubleTL(String value){
DecimalFormat df = new DecimalFormat("#.#", new DecimalFormatSymbols(new Locale("tr_TR")));
Double doublePrice = 0.0;
try {
doublePrice = df.parse(value).doubleValue();
} catch (ParseException e) {
Log.w(MainActivity.TAG,"Couldnt parse TL. Error is "+e.toString());
}
return doublePrice;
}
Upvotes: 1
Reputation: 2708
using DecimalFormatSymbols.getInstance()
will produce the default locale's correct symbols, so you will get it right for any platform you run on.
DecimalFormat df = new DecimalFormat("#.#", DecimalFormatSymbols.getInstance());
Upvotes: 4
Reputation: 8447
Use one of the other constructors of DecimalFormat:
new DecimalFormat("#.#", new DecimalFormatSymbols(Locale.US))
And then try and parse it using both separators.
Upvotes: 33