CODEWITHSUNDEEP
php
Alaa Gamal
Alaa Gamal

Reputation: 1125

Checking to see if a URL is Google

I want to check a URL to see if it is a Google url or not.

I've got this function

function isValidURL($url)
{
    return preg_match('|^http(s)?://google.com|i', $url);
}

If i try

if ( isValidURL('http://google.com/') ){
    echo 'yes its google url';
}

It works fine. But if I try

if ( isValidURL('http://www.google.com/') ){
    echo 'yes its google url';
}

(with www) I get an error!

Upvotes: 0

Views: 149

Answers (3)

jimbo2087
jimbo2087

Reputation: 1054

I like to use PHP's parse_url function to analyse url's. It returns an array with each part of the URL. This way you can be sure you're checking the correct part and it won't be thrown by https or query strings.

function isValidUrl($url, $domain_to_check){
       $url = parse_url($url);
       if (strstr($url['host'], $domain_to_search))
            return TRUE;
       return FALSE;
    }

Usage:

isValidUrl("http://www.google.com/q=google.com", "google.com");

Upvotes: 0

Kep
Kep

Reputation: 5857

If you're going to support googles subdomains, try:

preg_match('/^https?:\/\/(.+\.)*google\.com(\/.*)?$/is', $url)

Upvotes: 0

Martin.
Martin.

Reputation: 10529

Sure, because your regular expression is not ready to handle www.

Try

function isValidURL($url)
{
    return preg_match('|^http(s)?://(www\.)?google\.com|i', $url);
}

Upvotes: 4

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