Reputation: 104
I have this MySQL query:
SELECT DISTINCT hours.project_id
, projects.name
, sum(hours.spent_hours) AS expr1
, sum(hours.invoiced_hours) AS expr2
, hours.description
FROM
projects
INNER JOIN hours
ON projects.id = hours.project_id
GROUP BY
hours.project_id
, projects.id
, projects.name
, hours.description
How would you put pieces in FIND method in CakePHP? I tried several times but without any luck...
I have found this in documentation:
array(
'conditions' => array('Model.field' => $thisValue), //array of conditions
'recursive' => 1, //int
'fields' => array('Model.field1', 'DISTINCT Model.field2'), //array of field names
'order' => array('Model.created', 'Model.field3 DESC'), //string or array defining order
'group' => array('Model.field'), //fields to GROUP BY
'limit' => n, //int
'page' => n, //int
'offset'=>n, //int
'callbacks' => true //other possible values are false, 'before', 'after'
)
Other informations about databases:
Project hasMany Hours. Hours belongs to Project. In hours is project_id.
CakePHP 2.1.2.
Thank you! :)
Upvotes: 0
Views: 632
Reputation: 3174
I assume you are in the Project Model for the following lines.
$result = $this->find(
'all',
array(
'fields' => array(
'Hour.projetc_id',
'Project.id',
'Project.name',
'SUM(Hour.spent_hours) AS expr1',
'SUM(Hour.invoiced_hours) AS expr2',
'Hour.description'
),
'group' => array(
'Hour.projetc_id',
'Project.id',
'Project.name',
'Hour.description'
)
)
);
You may also want to have a look there to manage calculated fields in you array.
And lastly, I would recommend having a look at the Containable Behavior as it will speed up your DB query and allow to really get only what you need from the DB.
Upvotes: 1