CODEWITHSUNDEEP
java
AnithaRaj
AnithaRaj

Reputation: 147

posting url with string parameter that contains LINE BREAKS using java

i want to sent SMS from my JAVA APPLICATION in the following format:
NAME: Customer Name
ConfNO: 1234
Date: 2012-05-15
NoOfPax: Seven
Since i am using external sms gateway i need to post it as URL from the application. When i recive the SMS i dont see line breaks instead the text display \n. Please help.My Code is 

String senderid = "SMSALERT";
    String to = "97112345678";
    String text = "Reservation INFO\nName:Customer Name\nConfNO: KN1234\nTime: 12:00PM\n#Pax:5\nThank You for Choosing US";
    String type = "text";
    String ppgHost = "www.yahoo.com";
    String username = "username";
    String password = "password";
    String datetime = "2012-05-15 12:00:00";
    String path = "index.php";
    try {
        HttpClient httpClient = new DefaultHttpClient();
        List<NameValuePair> qparams = new ArrayList<NameValuePair>();
        qparams.add(new BasicNameValuePair("username", username));
        qparams.add(new BasicNameValuePair("password", password));
        qparams.add(new BasicNameValuePair("senderid", senderid));
        qparams.add(new BasicNameValuePair("to", to));
        qparams.add(new BasicNameValuePair("text", text));
        qparams.add(new BasicNameValuePair("type", type));
        qparams.add(new BasicNameValuePair("datetime", datetime));
        URI uri = URIUtils.createURI("http", ppgHost, -1, path, URLEncodedUtils.format(qparams, "UTF-8"), null);
        HttpPost httppost = new HttpPost(uri);
        System.out.println(httppost.getURI());
        HttpResponse response = httpClient.execute(httppost);
        System.out.println(response.getStatusLine());

Upvotes: 14

Views: 60059

Answers (2)

JKirchartz
JKirchartz

Reputation: 18042

If it's a URL you can use the percent-encoded value for a new line, it's %0D%0A although %0A (ASCII 10 - line feed) or %0D (ASCII 13 - carriage return) should work alone.

Upvotes: 35

cutebug
cutebug

Reputation: 475

All the parameters needs to be URL encoded. Further, it is a good practice to user system line separator rather than hardcoding "\n"

System.getProperty("line.separator");

Upvotes: 0

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