Reputation: 571
Having a document already indexed, at search i must part that document in two: first part consist of the first 100 words (tokens) and the rest of the document represents the second part. I have to score this two parts like this: the second part with 70% and the first with 30%.
EDIT 2: So i tried creating a Searcher that uses SpanPositionRangeQuery, but i must have understood SpanQuery usage all wrong because i can't get any hits (i used lukeall to verify if the words i was searching were indexed). Can someone give me a hand?
public static void search(String indexDir, String q) throws Exception
{
Directory dir = FSDirectory.open(new File(indexDir), null);
IndexSearcher is = new IndexSearcher(dir);
Term term = new Term("Field", q);
SpanPositionRangeQuery spanQuery = new SpanPositionRangeQuery(new SpanTermQuery(term), 0, 100);
spanQuery.setBoost(0.3f);CustomRomanianAnalyzer(Version.LUCENE_35));
long start = System.currentTimeMillis();
TopDocs hits = is.search(spanQuery, 10);
//TopDocs hits = is.search(query, 10);
long end = System.currentTimeMillis();
System.err.println("I found " + hits.totalHits + " documents (in " +
(end - start) + " milliseconds) '" +
q + "':");
for (int i=0;i<hits.scoreDocs.length;i++)
{
ScoreDoc scoreDoc = hits.scoreDocs[i];
Document doc = is.doc(scoreDoc.doc);
System.out.println(doc.get("filename"));
}
is.close();
}
I don't know how to combine query parser with SpanPositionRangeQuery to get what i need...
Upvotes: 0
Views: 390
Reputation: 57308
Yes, this can be done by setting the boost for each clause in a BooleanQuery. Using separate fields will work, but isn't strictly necessary. Lucene has a SpanPositionRangeQuery suitable for searching part of a document.
<SpanPositionRangeQuery: spanPosRange(field:term, 0, 100)^0.3>
Upvotes: 1