CODEWITHSUNDEEP
javascriptjquerydebuggingsyntax
Brian
Brian

Reputation: 3958

jQuery .offset() getting undefined for class `top` of var object

I'm working on the following code, and a bit stumped why I'm getting an error in my debugger. apparently in the line that starts with var skillsLimit = ... the class .top of var skillsOffset is undefined. Am I setting the var for skillsOffset incorrectly here?

// Set Pie graph to position fixed during a specified range
        var $window = $(window);
        var windowHeight = $(window).height();
        var pos = $window.scrollTop(); //position of the scrollbar
        var $this = $(this);

        $window.bind('scroll', function(){ //when the user is scrolling...
            var pos = $window.scrollTop(); //position of the scrollbar              
            var skillsOffset = $('#skills').offset();
            var skillsLimit = $('#skills').skillsOffset.top + $('#skills').outerHeight();
            if ( pos > skillsOffset ) {
                $('.chartwell-pies').css({ 'position' : 'fixed' });
            }               
        });

Upvotes: 1

Views: 11040

Answers (1)

Rob Cooper
Rob Cooper

Reputation: 28867

Remove the $('#skills') from the assignment to skillsLimit, you've already got the object in the line above:

var pos = $window.scrollTop(); //position of the scrollbar              
var skillsOffset = $('#skills').offset();
var skillsLimit = skillsOffset.top + $('#skills').outerHeight();

Upvotes: 3

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