CODEWITHSUNDEEP
c++templatesasynchronousc++11std
authchir
authchir

Reputation: 1635

Can std::async be use with template functions

Is std::async supose to work with template function? I've tried to lauch std::reverse as an asynchronous task bu got compile-time error.

I've tried to use simpler functions (foo and bar) and discover that only the non-template-function are working.

#include <algorithm>
#include <future>
#include <string>

void foo(std::string::iterator first, std::string::iterator last)
{
}

template<class BidirectionalIterator>
void bar(BidirectionalIterator first, BidirectionalIterator last)
{
}

int main()
{
    std::string str = "Lorem ipsum, dolor sit amet";

    auto result_reverse = std::async(std::reverse, str.begin(), str.end()); // Compile-time error
    auto result_foo     = std::async(foo, str.begin(), str.end());
    auto result_bar     = std::async(bar, str.begin(), str.end()); // Compile-time error

    result_reverse.get();
    result_foo.get();
    result_bar.get();
}

The compiler error is as follow:

main.cpp: In function ‘int main()’:
main.cpp:18:71: erreur: no matching function for call to ‘async(<unresolved overloaded function type>, std::basic_string<char>::iterator, std::basic_string<char>::iterator)’
main.cpp:18:71: note: candidates are:
/usr/include/c++/4.6/future:1355:5: note: template<class _Fn, class ... _Args> std::future<typename std::result_of<_Functor(_ArgTypes ...)>::type> std::async(std::launch, _Fn&&, _Args&& ...)
/usr/include/c++/4.6/future:1378:5: note: template<class _Fn, class ... _Args> typename std::__async_sfinae_helper<typename std::decay<_Functor>::type, _Fn, _Args ...>::type std::async(_Fn&&, _Args&& ...)
main.cpp:18:71: erreur: unable to deduce ‘auto’ from ‘<expression error>’
main.cpp:20:62: erreur: no matching function for call to ‘async(<unresolved overloaded function type>, std::basic_string<char>::iterator, std::basic_string<char>::iterator)’
main.cpp:20:62: note: candidates are:
/usr/include/c++/4.6/future:1355:5: note: template<class _Fn, class ... _Args> std::future<typename std::result_of<_Functor(_ArgTypes ...)>::type> std::async(std::launch, _Fn&&, _Args&& ...)
/usr/include/c++/4.6/future:1378:5: note: template<class _Fn, class ... _Args> typename std::__async_sfinae_helper<typename std::decay<_Functor>::type, _Fn, _Args ...>::type std::async(_Fn&&, _Args&& ...)
main.cpp:20:62: erreur: unable to deduce ‘auto’ from ‘<expression error>’

However, it pass when I manually specify the template instanciation, such as std::async(std::reverse<std::string::iterator>, str.begin(), str.end()).

Is this a compiler bug (GCC 4.6.3) or a well defined behaviour?

Upvotes: 12

Views: 3772

Answers (2)

Maxim Egorushkin
Maxim Egorushkin

Reputation: 136208

It can, but the invocation is a bit different:

auto result_reverse = std::async([&str]() {
        std::reverse(str.begin(), str.end());
    });

This is because std::reverse() is not a function, rather a function template that turns into a function when it is invoked as a function.

The above reverses a copy of the string and throws away the result. To pass the string by reference the lambda expression should be changed to start with [&str]().

Upvotes: 15

David Rodr&#237;guez - dribeas
David Rodr&#237;guez - dribeas

Reputation: 208323

std::reverse is not a function but a function template, you can use an specialization of that template (which is a function):

auto result_reverse = std::async(&std::reverse<std::string::iterator>, str.begin(), str.end());

Upvotes: 8

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