CODEWITHSUNDEEP
phphtml
sanders
sanders

Reputation: 10898

select multiple options

banging my head against the wall for something seemingly dead simple.

Here it is:

<html>
    <head></head>
    <body>
        <form method="post" action="action.php">
            <div><input type="checkbox" name="test" value="Newspaper"> <span >Newspaper</span></div>
            <div><input type="checkbox" name="test" value="PC"> <span >PC</span></div>
            <div><input type="checkbox" name="test" value="Home"> <span >Home</span></div>
            <div><input type="checkbox" name="test" value="Dont_know"> <span >dnunno</span></div>
            <input type="submit" name="Submit" value="send">
        </form>
    </body>
</html>

But when I select more then one option. I see in my print_r($_POST); statement only the last selected option in stead of all selected options. How should I deal with this?

update: I checked the rest of my code and i saw that this is done by some JavaScript. 

else if (aform.validatorArr[i][4] == "checkbox") {
    var fvs = "";
    eval("var chkbArray=aform." + aform.validatorArr[i][1] + ";");
    if (aform.validatorArr[i][2] == "cb_true") {
        for (k = 0; k < chkbArray.length; k++) {
            if (chkbArray[k].checked) {
                fvs += chkbArray[k].value;
                console.log(fvs);
            }
        }
        if (fvs == false) {
            s += aform.validatorArr[i][3] + "\n";
        }
    }
}

That's why the [] is not added in my html. But how could I modify this code so that it will take all options?

Upvotes: 2

Views: 362

Answers (1)

karim79
karim79

Reputation: 342635

Put [] after the name:

<input type="checkbox"  name="test[]" value="Newspaper">

See PHP FAQ for more details.

Upvotes: 15

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