Reputation: 10303
This is a noob question:
How to parse a date in format "YYYYmmdd"
without external libraries ? If the input string is not in this format I would like to get invalid Date
(or undefined if it will be easier).
Upvotes: 25
Views: 54178
Reputation: 192
This worked for me:
function parse(str) {
const year = str.substring(0, 4)
const month = str.substring(4, 6)
const day = str.substring(6, 8)
return new Date(`${year}-${month}-${day}`)
}
Upvotes: 0
Reputation: 147503
Using newer language features for destructuring assignment:
// Parse YYYYMMDD to Date
function parseYMD(s) {
let [C,Y,M,D] = s.match(/\d\d/g);
return new Date(C+Y, M-1, D);
}
['20211125', // Valid date
'2021112', // Invalid input
'20219999' // Invalid date components
].forEach(d =>
console.log(`${d} -> ${parseYMD(d).toDateString()}`)
);
Note that this does not validate the date components, any string with 8 or more digits will produce a valid Date. Anything else will produce an invalid Date. If strict parsing is required, consider:
// Parse YYYYMMDD to Date. If any part is out of
// range, return an invalid Date.
function parseYMD(s) {
let [C,Y,M,D] = s.match(/\d\d/g);
let d = new Date(C+Y, M-1, D);
let [yr,mo,da] = d.toLocaleDateString('en-CA').split(/\D/);
if (yr != C+Y || mo != M || da != D) {
d.setTime(NaN);
}
return d;
}
['20211125', // Valid date
'2021112', // Invalid input
'20219999' // Invalid date components
].forEach(d =>
console.log(`${d} -> ${parseYMD(d).toDateString()}`)
);
Upvotes: 1
Reputation: 1366
combining HBP's answer and this answer to get a function that parses YYYYMMDDHHmm and here is a fiddle
var parseTS=function(str){
// validate year as 4 digits, month as 01-12, and day as 01-31
if ((str = str.match (/^(\d{4})(0[1-9]|1[0-2])(0[1-9]|[12]\d|3[01])([01]\d|2[0-3])([0-5]\d)$/))) {
// make a date
str[0] = new Date (+str[1], +str[2] - 1, +str[3], +str[4], +str[5]);
// check if month stayed the same (ie that day number is valid)
if (str[0].getMonth () === +str[2] - 1) {
return str[0];
}
}
return undefined;
};
console.log(parseTS('201501012645'));
Upvotes: 0
Reputation: 20798
simplistic answer maybe, without checks, but fast...
var date = parseInt(date);
new Date(date / 10000, date % 10000 / 100, date % 100);
or, if months are not zero based in the source,
new Date(date / 10000, (date % 10000 / 100) - 1, date % 100);
Upvotes: 3
Reputation: 5475
function parse(str) {
if(!/^(\d){8}$/.test(str)) return "invalid date";
var y = str.substr(0,4),
m = str.substr(4,2),
d = str.substr(6,2);
return new Date(y,m,d);
}
Usage:
parse('20120401');
UPDATE:
As Rocket said, months are 0-based in js...use this if month's aren't 0-based in your string
function parse(str) {
if(!/^(\d){8}$/.test(str)) return "invalid date";
var y = str.substr(0,4),
m = str.substr(4,2) - 1,
d = str.substr(6,2);
return new Date(y,m,d);
}
UPDATE:
More rigorous checking for validity of date. Adopted HBP's way to validate date.
function parse(str) {
var y = str.substr(0,4),
m = str.substr(4,2) - 1,
d = str.substr(6,2);
var D = new Date(y,m,d);
return (D.getFullYear() == y && D.getMonth() == m && D.getDate() == d) ? D : 'invalid date';
}
Upvotes: 39
Reputation: 16043
A more robust version validating the numbers :
function parse (str) {
// validate year as 4 digits, month as 01-12, and day as 01-31
if ((str = str.match (/^(\d{4})(0[1-9]|1[0-2])(0[1-9]|[12]\d|3[01])$/))) {
// make a date
str[0] = new Date (+str[1], +str[2] - 1, +str[3]);
// check if month stayed the same (ie that day number is valid)
if (str[0].getMonth () === +str[2] - 1)
return str[0];
}
return undefined;
}
See fiddle at : http://jsfiddle.net/jstoolsmith/zJ7dM/
I recently wrote a much more capable version you can find here : http://jsfiddle.net/jstoolsmith/Db3JM/
Upvotes: 6