CODEWITHSUNDEEP
c#wpf
Amarnath
Amarnath

Reputation: 8865

How to know which file is selected in open dialog in c#

I have to open a file dialog. In that I have to choose one file either an XML or MAP file. If the choosen file is MAP file then I have to do step-A or if the choosen file is XML then I have to do step-B. My question is how to know which file is selected from the dialog box application?

OpenFileDialog fileDialog1 = new OpenFileDialog();
fileDialog1.Filter = "XML Files|*.xml|MAP Files|*.map";
fileDialog1.ShowDialog();

How to know which file is selected from the above filter ?

open file dialog

Upvotes: 0

Views: 2016

Answers (5)

Moustafa Khalil
Moustafa Khalil

Reputation: 164

Well, the above answers will work if luckily all the filters have different extensions. but if we are talking about different File versions with the same extension then we can get the selected filter through this code:

SaveFileDialog dlg = new SaveFileDialog();
        dlg.Filter = "Excel 97|*.xls|Excel 95|*.xls";
        if (dlg.ShowDialog() == System.Windows.Forms.DialogResult.OK)
        {
            //Filer index is 1 based.
            switch (dlg.FilterIndex)
            {
                case 1:
                    //Filter name: Excel 97
                    break;
                case 2:
                    //Filter name: Excel 95
                    break;
            }
        }

Upvotes: 0

Davio
Davio

Reputation: 4737

You could even use similar extensions in a switch with stacked labels and use the default case for unsupported file types:

switch (extension)
{
    case "xml":
    case "xaml":
        Debug.WriteLine("It's an XML!");
        break;
    case "map":
        Debug.WriteLine("It's a map!");
        break;
    default:
        MessageBox.Show("Please select an XML or MAP file");
        // Show the dialog again
        break;
}

Upvotes: 0

Nikhil Agrawal
Nikhil Agrawal

Reputation: 48568

I think you can't do that while it is open.

When user presses OK then pass OpenFileDialog.Filename in Path.GetExtension method or OpenFileDialog.Filename.Endswith(".xml").

Check if extension is XML then do x step otherwise y step.

EDIT

See for functionality that you require, there has to be an event in open file dialog.

There are 2 OpenFileDialog Class

  1. System.Windows.Forms
  2. Microsoft.Win32

Both have only one event OpenFileDialog.FileOK which you can look for.

Upvotes: 1

Green Su
Green Su

Reputation: 2348

        openFileDialog1.FileName = "";
        if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
        {
            string filename = openFileDialog1.FileName;

            if (File.Exists(filename))
            {
                //do something here
            }
        }

The FileName attribute of OpenFileDialog is the file name selected.

Upvotes: 0

dtsg
dtsg

Reputation: 4468

You can use:

   string fileName = OpenFileDialog.Filename;

    if(fileName.EndsWith(".xml"))
    {
    //
    }
    else if(fileName.EndsWith(".map"))
    {
     //
    }

Upvotes: 2

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