CODEWITHSUNDEEP
sqlpostgresql
Dfr
Dfr

Reputation: 4185

Sql compress multiple similar subqueries into single subquery

Good day, my question is about optimizing sql query. The following query is slow:

SELECT id, name,
, (SELECT rank_time FROM stage_rank WHERE stage = stage.id ORDER BY rank_time DESC LIMIT 1)::date AS rank_time
, (SELECT host_c    FROM stage_rank WHERE stage = stage.id ORDER BY rank_time DESC LIMIT 1) AS host_c
, (SELECT index_pa  FROM stage_rank WHERE stage = stage.id ORDER BY rank_time DESC LIMIT 1) AS index_pa
, (SELECT links_pa  FROM stage_rank WHERE stage = stage.id ORDER BY rank_time DESC LIMIT 1) AS links_pa
, (SELECT index_pb  FROM stage_rank WHERE stage = stage.id ORDER BY rank_time DESC LIMIT 1) AS index_pb
, (SELECT links_pb  FROM stage_rank WHERE stage = stage.id ORDER BY rank_time DESC LIMIT 1) AS links_pb
FROM stage
ORDER BY name;

I think it mostly because of repeated select from stage_rank, is it possible to make this select done once, and get all fields in single hit ?

Also any postgresql specific feaures might be of help here ?

Upvotes: 3

Views: 155

Answers (1)

Quassnoi
Quassnoi

Reputation: 425643

In PostgreSQL, you can select the whole record as a field and expand it later:

SELECT  id, name, (sr).*
FROM    (
        SELECT  id, name,
                (
                SELECT  stage_rank
                FROM    stage_rank
                WHERE   stage = stage.id
                ORDER BY
                        rank_time DESC
                LIMIT 1
                ) sr
        FROM    stage
        ) q
ORDER BY
        name

or rewrite the query:

SELECT  DISTINCT ON (s.name, s.id, sr.rank_time, sr.id)
        s.id, s.name, sr.*
FROM    stage s
JOIN    stage_rank sr
ON      sr.stage = s.id
ORDER BY
        s.name, s.id, sr.rank_time DESC, sr.id DESC

or rewrite it the other way:

SELECT  id, name, (sr).*
FROM    (
        SELECT  s.id, s.name, sr, ROW_NUMBER() OVER (PARTITION BY s.id ORDER BY sr.rank_time DESC, sr.id DESC) rn
        FROM    stage
        JOIN    stage_rank sr
        ON      sr.stage = s.id
        ) q
WHERE   rn = 1
ORDER BY
        name

Upvotes: 9

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