Reputation: 8477
I need to convert time value strings given in the following format to seconds, for example:
1.'00:00:00,000' -> 0 seconds
2.'00:00:10,000' -> 10 seconds
3.'00:01:04,000' -> 64 seconds
4.'01:01:09,000' -> 3669 seconds
Do I need to use regex to do this? I tried to use the time module, but
time.strptime('00:00:00,000','%I:%M:%S')
throws:
ValueError: time data '00:00:00,000' does not match format '%I:%M:%S'
Edit:
Looks like this:
from datetime import datetime
pt = datetime.strptime(timestring,'%H:%M:%S,%f')
total_seconds = pt.second + pt.minute*60 + pt.hour*3600
gives the correct result. I was just using the wrong module.
Upvotes: 84
Views: 209368
Reputation: 174708
import datetime
import time
x = time.strptime('00:01:00,000'.split(',')[0],'%H:%M:%S')
datetime.timedelta(hours=x.tm_hour,minutes=x.tm_min,seconds=x.tm_sec).total_seconds()
60.0
Upvotes: 87
Reputation: 1016
.total_seconds()
seems to be straightforward.
from datetime import datetime
FMT = '%H:%M:%S.%f'
#example
s2 = '11:01:49.897'
s1 = '10:59:26.754'
# calculate difference
pt = datetime.strptime(s2, FMT) - datetime.strptime(s1, FMT)
# compute seconds number (answer)
total_seconds = pt.total_seconds()
# output: 143.143
Upvotes: 4
Reputation: 969
Why not use functools.reduce
?
from functools import reduce
def str_to_seconds(t):
reduce(lambda prev, next: prev * 60 + next, [float(x) for x in t.replace(',', '.').split(":")], 0)
One function, works on either 10,40
, 09:12,40
or 02:08:14,59
. If you use .
instead of ,
for decimal sign it's even more simpler:
def str_to_seconds(t):
reduce(lambda prev, next: prev * 60 + next, [float(x) for x in t.split(":")], 0)
Upvotes: 0
Reputation: 2213
Dynamic solution for HH:MM:SS and MM:SS. If you want to handle a command, use split(',')
divide by 1000 or something and then add.
_time = 'SS'
_time = 'MM:SS'
_time = 'HH:MM:SS'
seconds = sum(int(x) * 60 ** i for i, x in enumerate(reversed(_time.split(':'))))
# multiple timestamps
_times = ['MM:SS', 'HH:MM:SS', 'SS']
_times = [sum(int(x) * 60 ** i for i, x in enumerate(reversed(_time.split(':')))) for _time in times]
Upvotes: 0
Reputation: 1937
def time_to_sec(t):
h, m, s = map(int, t.split(':'))
return h * 3600 + m * 60 + s
t = '10:40:20'
time_to_sec(t) # 38420
Upvotes: 8
Reputation: 1702
def time_to_sec(time):
sep = ','
rest = time.split(sep, 1)[0]
splitted = rest.split(":")
emel = len(splitted) - 1
i = 0
summa = 0
for numb in splitted:
szor = 60 ** (emel - i)
i += 1
summa += int(numb) * szor
return summa
Upvotes: 0
Reputation: 2082
Inspired by sverrir-sigmundarson's comment:
def time_to_sec(time_str):
return sum(x * int(t) for x, t in zip([1, 60, 3600], reversed(time_str.split(":"))))
Upvotes: 2
Reputation: 189
import time
from datetime import datetime
t1 = datetime.now().replace(microsecond=0)
time.sleep(3)
now = datetime.now().replace(microsecond=0)
print((now - t1).total_seconds())
result: 3.0
Upvotes: 4
Reputation: 469
without imports
time = "01:34:11"
sum(x * int(t) for x, t in zip([3600, 60, 1], time.split(":")))
Upvotes: 36
Reputation: 414745
To get the timedelta()
, you should subtract 1900-01-01
:
>>> from datetime import datetime
>>> datetime.strptime('01:01:09,000', '%H:%M:%S,%f')
datetime.datetime(1900, 1, 1, 1, 1, 9)
>>> td = datetime.strptime('01:01:09,000', '%H:%M:%S,%f') - datetime(1900,1,1)
>>> td
datetime.timedelta(0, 3669)
>>> td.total_seconds() # 2.7+
3669.0
%H
above implies the input is less than a day, to support the time difference more than a day:
>>> import re
>>> from datetime import timedelta
>>> td = timedelta(**dict(zip("hours minutes seconds milliseconds".split(),
... map(int, re.findall('\d+', '31:01:09,000')))))
>>> td
datetime.timedelta(1, 25269)
>>> td.total_seconds()
111669.0
To emulate .total_seconds()
on Python 2.6:
>>> from __future__ import division
>>> ((td.days * 86400 + td.seconds) * 10**6 + td.microseconds) / 10**6
111669.0
Upvotes: 15
Reputation: 459
A little more pythonic way I think would be:
timestr = '00:04:23'
ftr = [3600,60,1]
sum([a*b for a,b in zip(ftr, map(int,timestr.split(':')))])
Output is 263Sec.
I would be interested to see if anyone could simplify it further.
Upvotes: 45
Reputation: 54117
There is always parsing by hand
>>> import re
>>> ts = ['00:00:00,000', '00:00:10,000', '00:01:04,000', '01:01:09,000']
>>> for t in ts:
... times = map(int, re.split(r"[:,]", t))
... print t, times[0]*3600+times[1]*60+times[2]+times[3]/1000.
...
00:00:00,000 0.0
00:00:10,000 10.0
00:01:04,000 64.0
01:01:09,000 3669.0
>>>
Upvotes: 5
Reputation: 43097
It looks like you're willing to strip fractions of a second... the problem is you can't use '00' as the hour with %I
>>> time.strptime('00:00:00,000'.split(',')[0],'%H:%M:%S')
time.struct_time(tm_year=1900, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=0, tm_yday=1, tm_isdst=-1)
>>>
Upvotes: 6