CODEWITHSUNDEEP
phparrays
Klausos Klausos
Klausos Klausos

Reputation: 16040

PHP: Transformation of array

There is the following array:

arr1 = array(array('xxx',3),array('yyy',2));

I need to transform it into the array arr2, where the number of occurrence of each entry is equal to the 2nd column value in array arr1. For instance, for the above given arr1, arr2 should be the following:

arr2 = array(array('xxx'),array('xxx'),array('xxx'),array('yyy'),array('yyy'));

I wrote the following code, but my question is: Is it possible to do the same in a simpler way?

for ($i=0; $i<count($arr1); $i++) {
  for ($j=0; $j<$arr1[i][1]; $j++) {
     $arr2[] = array($arr1[0]);
  }
}

Upvotes: 1

Views: 120

Answers (2)

Teun Zengerink
Teun Zengerink

Reputation: 4393

I think a foreach is simpler and easier to read.

$arr1 = array(array('xxx', 3), array('yyy', 2));
$arr2 = array();

foreach ($arr1 as $arr)
{
    for ($i = 0; $i < $arr[1]; $i++)
    {
        $arr2[] = array($arr[0]);
    }
}

Upvotes: 3

goat
goat

Reputation: 31813

foreach ($arr1 as $entry) {
    $arr2[] = array_fill(0, $entry[1], array($entry[0]));
}
$arr2 = call_user_func_array('array_merge', $arr2);

I wouldn't use it though. It's much less readable.

Upvotes: 1

Related Questions