Reputation:
How can I get decimal from string hexdecimal:
I have unsigned char* hexBuffer = "eb89f0a36e463d";.
And I have unsigned char* hex[5] ={'\\','x'};.
I copy from hexBuffer
first two char "eb"
to hex[2] = 'e'; hex[3] = 'b';
.
Now i have string "\xeb"
or "\xEB"
inside hex.
As we all know 0xEB
its ahexdecimal and we can convert to 235
decimal.
How can I convert "\xEB"
to 235(int)
?
(Thanks to jedwards)
My Answer (maybe it will be useful for someone):
/*only for lower case & digits*/
unsigned char hash[57] ="e1b026972ba2c787780a243e0a80ec8299e14d9d92b3ce24358b1f04";
unsigned char chr =0;
int dec[28] ={0}; int i = 0;int c =0;
while( *hash )
{
c++;
(*hash >= 0x30 && *hash <= 0x39) ? ( chr = *hash - 0x30) : ( chr = *hash - 0x61 + 10);
*hash++;
if ( c == 1) dec[i] = chr * 16; else{ dec[i] += chr; c = 0; dec[i++];}
}
Upvotes: 3
Views: 467
Reputation: 227608
In C++11 you can use one of the string to unsigned integral type and integral conversion functions:
long i = std::stol("ff", nullptr, 16); // convert base 16 string. Accepts 0x prefix.
Of course, this requires that your string represents a number that can fit into the integer type on the LHS of the expression.
Upvotes: 5
Reputation: 30250
Typically I see homebrew implementations of hex2dec functions look like:
#include <stdio.h>
unsigned char hex2dec_nibble(unsigned char n)
{
// Numbers
if(n >= 0x30 && n <= 0x39)
{
return (n-0x30);
}
// Upper case
else if(n >= 0x41 && n <= 0x46)
{
return (n-0x41+10);
}
// Lower case
else if(n >= 0x61 && n <= 0x66)
{
return (n-0x61+10);
}
else
{
return -1;
}
}
int main()
{
unsigned char t;
t = '0'; printf("%c = %d\n", t, hex2dec_nibble(t));
t = 'A'; printf("%c = %d\n", t, hex2dec_nibble(t));
t = 'F'; printf("%c = %d\n", t, hex2dec_nibble(t));
t = 'G'; printf("%c = %d\n", t, hex2dec_nibble(t));
t = 'a'; printf("%c = %d\n", t, hex2dec_nibble(t));
t = 'f'; printf("%c = %d\n", t, hex2dec_nibble(t));
t = 'g'; printf("%c = %d\n", t, hex2dec_nibble(t));
t = '='; printf("%c = %d\n", t, hex2dec_nibble(t));
}
Which displays:
0 = 0
A = 10
F = 15
G = 255
a = 10
f = 15
g = 255
= = 255
I'll leave it as an exercise for you to go from nibble to byte and then from byte to arbitrary length string.
Note: I only used #include
and printf
to demonstrate the functionality of the hex2dec_nibble
function. Its not necessary to use these.
Upvotes: 3
Reputation: 17131
The function you want is called sscanf.
http://www.cplusplus.com/reference/clibrary/cstdio/sscanf/
int integer;
sscanf(hexBuffer, "%x", &integer);
Upvotes: 8