CODEWITHSUNDEEP
phpdate
Brett
Brett

Reputation: 3316

Date functions in PHP

Another simple question. I found this really cool snippet of code:

$date_str = "Jan 14th 2011";
$date = date_parse_from_format('M jS Y', $date_str);
echo $date->format('Y-m-d');

But when I run it on my computer it says Fatal error: Call to a member function format() on a non-object line 3.

The code was taken from here Converting date string to date so I presume it is good but it looks like it is referencing to an object that does not exist.

I have been looking at http://php.net/manual/en/function.date-parse-from-format.php and http://www.w3schools.com/php/php_ref_date.asp amongst many others but I have not found any any clues.

My question is should this code work as a standalone piece of code. If so why does it not work for me? Else, should I do to get it to work as expected.

Upvotes: 1

Views: 168

Answers (2)

Ibrahim Azhar Armar
Ibrahim Azhar Armar

Reputation: 25745

date_parse_from_format();

returns associative array and you are trying to access the class method on a non object.

if you want to make use of PHP's inbuilt DateTime class. then more information here https://www.php.net/manual/en/datetime.format.php

Upvotes: 3

Marc B
Marc B

Reputation: 360572

date_parse_from_format returns an array, not a DateTime object. What you want is

$date = date_create_from_format('M jS Y', $date_str);
             ^^^^^^---note the change
echo date('Y-m-d', $date);

Upvotes: 2

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