CODEWITHSUNDEEP
pythonregex
P Li
P Li

Reputation: 5222

why this regex cannot find the result

I have a python code like below: My question is why the matched variable is [' ']? (I used the regex in regexpal.com, it can find the right result |Name=A. Johnson | there)

import re
a = 
'{{Infobox U.S. Cabinet |align=left |clear=yes |Name=A. Johnson |President=Andrew Johnson |President start=1865 |President end=1869 |Vice President=None |Vice President start=1865 |Vice President end=1869 |State=[[William H. Seward]] |State start=1865 |State end=1869 |War=[[Edwin M. Stanton]] |War start=1865 |War end=1868 |War 2=[[John Schofield|John M. Schofield]] |War start 2=1868 |War end 2=1869 |Treasury=[[Hugh McCulloch]] |Treasury start=1865 |Treasury end=1869 |Justice=[[James Speed]] |Justice start=1865 |Justice end=1866 |Justice 2=[[Henry Stanberry]] |Justice start 2=1866 |Justice end 2=1868 |Justice 3=[[William M. Evarts]] |Justice start 3=1868 |Justice end 3=1869 |Post=[[William Dennison (Ohio governor)|William Dennison]] |Post start=1865 |Post end=1866 |Post 2=[[Alexander Randall|Alexander W. Randall]] |Post start 2=1866 |Post end 2=1869 |Navy=[[Gideon Welles]] |Navy start=1865 |Navy end=1869 |Interior=[[John P. Usher]] |Interior date=1865 |Interior 2=[[James Harlan (senator)|James Harlan]] |Interior start 2=1865 |Interior end 2=1866 |Interior 3=[[Orville H. Browning]] |Interior start 3=1866 |Interior end 3=1869 }}'
matched = re.findall("\|?\s*name\s*=(.)*?\|",a,re.I)

Upvotes: 2

Views: 163

Answers (3)

Asterisk
Asterisk

Reputation: 3574

matched = re.findall("\|?\s*[nN]ame\s*=([a-zA-Z\.\s]+)\|?",a,re.I)
print matched

output:

['A. Johnson ']

Upvotes: 0

U2EF1
U2EF1

Reputation: 13261

Looks to be how it's handling grouping. As a simpler example, look at the difference between the output of the following lines of code:

re.findall("c(a)*t", "hi caaat hi")
re.findall("c(a*)t", "hi caaat hi")

It looks like the code you want would be more like:

re.findall("\|\s*name\s*=([^\|\}]*)", a, re.I)

Upvotes: 0

Asherah
Asherah

Reputation: 19347

You'll want (.*?), not (.)*?—the latter (what you have) will only capture a single character, even if it consumes more than a single one. A capture group will only be returned once even if the group itself has a repeat; so the latter captures a single character (.) despite its repeat.

If you move the repeat into the capture group with (.*?), you'll get more than a single character in the return.

Upvotes: 3

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