Regarding XML Diff & Patch

Question

I got the example from MSDN about how to compare two XML with XML Diff and Patch. MSDN XML Diff & Path

It is an easy example but I dont get what I expect.

I have the following XMls:

<a>
<component>A</component>
<component>4</component>
</a>

and

<a>
<component>A</component>
<component>5</component>
</a>

Running the tool code I dont get exaclty the difference. The output which I get is:

<a>
<component>A</component>
<component>5</component>
</a>

But for my purposes I would like to get just the difference which differs from the original, in this case.

<a>
<component>4</component>
</a>

Does anyone know how I can adapt the code to my solution.

Thank you very much.

edit code used:

• (Here I find out the differences between the files)

  public void GenerateDiffGram(string originalFile, string finalFile, 
                              XmlWriter diffGramWriter)
  {
      XmlDiff xmldiff = new XmlDiff(XmlDiffOptions.IgnoreChildOrder | 
                                   XmlDiffOptions.IgnoreNamespaces | 
                                   XmlDiffOptions.IgnorePrefixes);
     bool bIdentical = xmldiff.Compare(originalFile, newFile, false, diffgramWriter);
     diffgramWriter.Close();
  }
  

• Patching up the original file to create the new changed file.

  public void PatchUp(string originalFile, String diffGramFile, String OutputFile)
  {
  XmlDocument sourceDoc = new XmlDocument(new NameTable());
  sourceDoc.Load(originalFile);
  XmlTextReader diffgramReader = new XmlTextReader(diffGramFile);
  
  xmlpatch.Patch(sourceDoc,diffgramReader);
  
  XmlTextWriter output = new XmlTextWriter(OutputFile,Encoding.Unicode);
  sourceDoc.Save(output);
  output.Close();
  }