CODEWITHSUNDEEP
jsonscala
Bob
Bob

Reputation: 8504

Scala convert tuple to JSON using Jerkson

Code snippet in REPL

scala> import com.codahale.jerkson.Json._
scala> val t = (1, 3.14, "Fred")
scala> generate(t)
res5: String = {"_1":1,"_2":3.14,"_3":"Fred"}

In the output, I want to assign labels to attributes instead of _1, _2, _3. How would I go about doing this?

Upvotes: 4

Views: 2810

Answers (1)

Jean-Philippe Pellet
Jean-Philippe Pellet

Reputation: 60006

Use a case class instead of a tuple:

case class Named(myInt: Int, thisDouble: Double, desc: String)
generate(Named(1, 3.14, "Fred"))

Gives:

{"myInt": 1.0,"thisDouble":3.14,"desc":"Fred"}

Upvotes: 2

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