Reputation: 4461
To find the longest path in a DAG, I'm aware of 2 algorithms: algo 1: do a topological sort + use dynamic programming on the result of the sort ~ or ~ algo 2: enumerate all the paths in the DAG using DFS, and record the longest. It seems like enumerating all the paths with DFS has better complexity than algo 1. Is that true?
Upvotes: 16
Views: 35915
Reputation: 4461
Enumerate all paths in a DAG using "DFS":
import numpy as np
def enumerate_dag(g):
def enumerate_r(n, paths, visited, a_path = []):
a_path += [n]
visited[n] = 1
if not g[n]:
paths += [list(a_path)]
else:
for nn in g[n]:
enumerate_r(nn, paths, visited, list(a_path))
paths, N = [], len(g)
visited = np.zeros((N), dtype='int32')
for root in range(N):
if visited[root]: continue
enumerate_r(root, paths, visited, [])
return paths
Upvotes: 3
Reputation: 726479
Your second option is incorrect: DFS does not explore all possible paths, unless your graph is a tree or a forest, and you start from the roots. The second algorithm that I know is negating the weights and finding the shortest path, but it is somewhat slower than the top sort + DP algorithm that you listed as #1.
Upvotes: 11
Reputation: 179
No DFS needed. Algorithm : takes a DAG G. Each arc holds one variable E
for each node with no predecessor :
for each of his leaving arcs, E=1.
for each node whose predecessors have all been visited :
for each of his leaving arcs, E=max(E(entering arcs))+1.
max_path is the highest E within edges when all nodes have been processed.
Upvotes: 3