Reputation: 8855
I created a MainWindow.xaml file in visual studio. Then I clicked on run its working good. I created another file called SecondMainWindow.xaml, now I want to run the SecondMainWindow.xaml as the start file. But when I click run the MainWindow.xaml file is opening. So I excluded that file from the project. Now if I click run then it throw-ed an error saying
MainWindow.xaml does not exist.
Yes that is true because I have excluded it from my project.
But my question how to make SecondMainWindow.xaml as the file that should be opened first when I click on run.
Upvotes: 2
Views: 5931
Reputation: 48558
In App.xaml under StartupUri
attribute of Application
tag change MainWindow.xaml
to SecondMainWindow.xaml
.
<Application StartupUri = "SecondMainWindow.xaml" >
</Application>
BTW there was no need of removing MainWindow.xaml
from project. You can have n number of xaml files. What you define in StartupUri
property is the file which is run first.
Upvotes: 5
Reputation: 31
Go to the App.xaml file and change StartupUri="MainWindow.xaml" to StartupUri="SecondMainWindow.xaml"
Upvotes: 2