CODEWITHSUNDEEP
javaregexsplit
Ina
Ina

Reputation: 27

Split, doesn't work first character

I have a problem with the method split. I have this regex:

String regex = "[\s|\,]+";

And I have these two strings:

String s1 = "19/2009 , 34.40";

String s2 = ",19/2009 , 34.40";   // this is the same string wiht "," in the start

I apply the regex to the two strings:

String r1[] = s1.split(regex);  
String r2[] = s2.split(regex);

In the first case I get r1[0]="19/2009" and r1[1]="34.40", this is the correct result. But in the second case I get r2[0]="", r2[1]="19/2009" and r2[2]="34.40". This is wrong, it should be the same result for the second string as for the first, without the empty string. What do I need to change for that?

Upvotes: 1

Views: 449

Answers (3)

user219882
user219882

Reputation: 15844

I would leave the regex as it is and do this

List<String> list = new ArrayList<String>(Arrays.asList(splitArray));
for (Iterator<String> iterator = list.iterator(); iterator.hasNext();) {
    if (iterator.next().isEmpty()) { // remove empty indexes
        iterator.remove();
    }
}

It's a little bit longer but it gives you a List as an output which is much better that an array.

Upvotes: 0

mayhewr
mayhewr

Reputation: 4021

using Apache Commons' StringUtils...

String r2[] = StringUtils.strip(s2, ", ").split(regex);

Upvotes: 1

Vishal Sharma
Vishal Sharma

Reputation: 112

Since you gave , as a regex, , splits your string in two, so your string ,19/2009 is split into two parts. The first part is before ,, which is nothing so "", and the second part, which is 19/2009, is in r2[1] and the third, separated by another ,, is in r2[2]=34.40. Everything is working right.

Upvotes: 2

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