How to convert int[] into List<Integer> in Java?

Question

How do I convert int[] into List<Integer> in Java?

Of course, I'm interested in any other answer than doing it in a loop, item by item. But if there's no other answer, I'll pick that one as the best to show the fact that this functionality is not part of Java.

Answer 1

The traditional way of adding elements from an Array to the List

List<Integer> traditionalList = new ArrayList<>();
for(int i: nums) {
     traditionalList.add(i);
}
System.out.println("Traditional way of adding elements from array to list: " + traditionalList);

Using Stream.collect():

List<Integer> intList = Arrays.stream(nums).boxed().collect(Collectors.toList()); // Using Collectors stream and Arrays.stream()
List<Integer> intList1 =IntStream.of(nums).boxed().collect(Collectors.toList()); // Using Collectors stream and IntStream.of()
System.out.println("Using Stream.collect(): " + intList + " \t" + intList1);

Using Stream.toArray()

List<Integer> collectionIntList = new ArrayList<>();
Collections.addAll(collectionIntList, Arrays.stream(nums).boxed().toArray(Integer[]::new)); // Returns Integer[], addAll to new List
System.out.println("Using Stream.toArray() and new keyword" + collectionIntList); //using toArray

Answer 2

What about this:

int[] a = {1,2,3};
Integer[] b = ArrayUtils.toObject(a);
List<Integer> c = Arrays.asList(b);

Answer 3

The best shot:

    /**
     * Integer modifiable fixed length list of an int array or many int's.
     *
     * @author Daniel De Leon.
     */
    public class IntegerListWrap extends AbstractList<Integer> {
    
        int[] data;
    
        public IntegerListWrap(int... data) {
            this.data = data;
        }
    
        @Override
        public Integer get(int index) {
            return data[index];
        }
    
        @Override
        public Integer set(int index, Integer element) {
            int r = data[index];
            data[index] = element;
            return r;
        }
    
        @Override
        public int size() {
            return data.length;
        }
    }

• Support get and set.
• No memory data duplication.
• No wasting time in loops.

Examples:

int[] intArray = new int[]{1, 2, 3};
List<Integer> integerListWrap = new IntegerListWrap(intArray);
List<Integer> integerListWrap1 = new IntegerListWrap(1, 2, 3);

Answer 4

You could use IntStream of and boxed it to Integer after that sorted using reverseOrder comparator.

List<Integer> listItems = IntStream.of(arrayItems)
                .boxed()
                .sorted(Collections.reverseOrder())
                .collect(Collectors.toList());

This approach has the advantage of being more flexible, as you can use different collectors to create different types of lists (e.g., an ArrayList, a LinkedList, etc.).

Answer 5

Streams

1. In Java 8+ you can make a stream of your int array. Call either Arrays.stream or IntStream.of.
2. Call IntStream#boxed to use boxing conversion from int primitive to Integer objects.
3. Collect into a list using Stream.collect( Collectors.toList() ). Or more simply in Java 16+, call Stream#toList().

Example:

int[] ints = {1,2,3};
List<Integer> list = Arrays.stream(ints).boxed().collect(Collectors.toList());

In Java 16 and later:

List<Integer> list = Arrays.stream(ints).boxed().toList();

Answer 6

Arrays.stream(ints).forEach(list::add);

Answer 7

int[] arr = { 1, 2, 3, 4, 5 };

List<Integer> list = Arrays.stream(arr)     // IntStream
                            .boxed()        // Stream<Integer>
                            .collect(Collectors.toList());

see this

Answer 8

There is no shortcut for converting from int[] to List<Integer> as Arrays.asList does not deal with boxing and will just create a List<int[]> which is not what you want. You have to make a utility method.

int[] ints = {1, 2, 3};
List<Integer> intList = new ArrayList<Integer>(ints.length);
for (int i : ints)
{
    intList.add(i);
}

Answer 9

If you are using java 8, we can use the stream API to convert it into a list.

List<Integer> list = Arrays.stream(arr)     // IntStream 
                                .boxed()        // Stream<Integer>
                                .collect(Collectors.toList());

You can also use the IntStream to convert as well.

List<Integer> list = IntStream.of(arr) // return Intstream
                                    .boxed()        // Stream<Integer>
                                    .collect(Collectors.toList());

There are other external library like guava and apache commons also available convert it.

cheers.

Answer 10

Here is another possibility, again with Java 8 Streams:

void intArrayToListOfIntegers(int[] arr, List<Integer> list) {
    IntStream.range(0, arr.length).forEach(i -> list.add(arr[i]));
}

Answer 11

Here is a solution:

int[] array = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };

Integer[] iArray = Arrays.stream(array).boxed().toArray(Integer[]::new);
System.out.println(Arrays.toString(iArray));

List<Integer> list = new ArrayList<>();
Collections.addAll(list, iArray);
System.out.println(list);

Output:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Answer 12

In Java 8 :

int[] arr = {1,2,3};
IntStream.of(arr).boxed().collect(Collectors.toList());

Answer 13

   /* Integer[] to List<Integer> */



        Integer[] intArr = { 10, 20, 30, 40, 50, 60, 70, 80, 90, 100 };
        List<Integer> arrList = new ArrayList<>();
        arrList.addAll(Arrays.asList(intArr));
        System.out.println(arrList);


/* Integer[] to Collection<Integer> */


    Integer[] intArr = { 10, 20, 30, 40, 50, 60, 70, 80, 90, 100 };
    Collection<Integer> c = Arrays.asList(intArr);

Answer 14

If you're open to using a third party library, this will work in Eclipse Collections:

int[] a = {1, 2, 3};
List<Integer> integers = IntLists.mutable.with(a).collect(i -> i);
Assert.assertEquals(Lists.mutable.with(1, 2, 3), integers);

Note: I am a committer for Eclipse Collections.

Answer 15

The smallest piece of code would be:

public List<Integer> myWork(int[] array) {
    return Arrays.asList(ArrayUtils.toObject(array));
}

where ArrayUtils comes from commons-lang :)

Answer 16

I'll add another answer with a different method; no loop but an anonymous class that will utilize the autoboxing features:

public List<Integer> asList(final int[] is)
{
    return new AbstractList<Integer>() {
            public Integer get(int i) { return is[i]; }
            public int size() { return is.length; }
    };
}

Answer 17

Here is a generic way to convert array to ArrayList

<T> ArrayList<T> toArrayList(Object o, Class<T> type){
    ArrayList<T> objects = new ArrayList<>();
    for (int i = 0; i < Array.getLength(o); i++) {
        //noinspection unchecked
        objects.add((T) Array.get(o, i));
    }
    return objects;
}

Usage

ArrayList<Integer> list = toArrayList(new int[]{1,2,3}, Integer.class);

Answer 18

In Java 8 with stream:

int[] ints = {1, 2, 3};
List<Integer> list = new ArrayList<Integer>();
Collections.addAll(list, Arrays.stream(ints).boxed().toArray(Integer[]::new));

or with Collectors

List<Integer> list =  Arrays.stream(ints).boxed().collect(Collectors.toList());

Answer 19

Also from guava libraries... com.google.common.primitives.Ints:

List<Integer> Ints.asList(int...)

Answer 20

give a try to this class:

class PrimitiveWrapper<T> extends AbstractList<T> {

    private final T[] data;

    private PrimitiveWrapper(T[] data) {
        this.data = data; // you can clone this array for preventing aliasing
    }

    public static <T> List<T> ofIntegers(int... data) {
        return new PrimitiveWrapper(toBoxedArray(Integer.class, data));
    }

    public static <T> List<T> ofCharacters(char... data) {
        return new PrimitiveWrapper(toBoxedArray(Character.class, data));
    }

    public static <T> List<T> ofDoubles(double... data) {
        return new PrimitiveWrapper(toBoxedArray(Double.class, data));
    }  

    // ditto for byte, float, boolean, long

    private static <T> T[] toBoxedArray(Class<T> boxClass, Object components) {
        final int length = Array.getLength(components);
        Object res = Array.newInstance(boxClass, length);

        for (int i = 0; i < length; i++) {
            Array.set(res, i, Array.get(components, i));
        }

        return (T[]) res;
    }

    @Override
    public T get(int index) {
        return data[index];
    }

    @Override
    public int size() {
        return data.length;
    }
}

testcase:

List<Integer> ints = PrimitiveWrapper.ofIntegers(10, 20);
List<Double> doubles = PrimitiveWrapper.ofDoubles(10, 20);
// etc

Answer 21

Arrays.asList will not work as some of the other answers expect.

This code will not create a list of 10 integers. It will print 1, not 10:

int arr[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
List lst = Arrays.asList(arr);
System.out.println(lst.size());

This will create a list of integers:

List<Integer> lst = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);

If you already have the array of ints, there is not quick way to convert, you're better off with the loop.

On the other hand, if your array has Objects, not primitives in it, Arrays.asList will work:

String str[] = { "Homer", "Marge", "Bart", "Lisa", "Maggie" };
List<String> lst = Arrays.asList(str);

Answer 22

It's also worth checking out this bug report, which was closed with reason "Not a defect" and the following text:

"Autoboxing of entire arrays is not specified behavior, for good reason. It can be prohibitively expensive for large arrays."