CODEWITHSUNDEEP
phpmysql
Nathan Link Abiola
Nathan Link Abiola

Reputation: 43

PHP MySQL query submit buttons

I have constructed the following query

if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1")) {
$insertSQL = sprintf("INSERT INTO selection (student_id, id_project, level_of_want) 
VALUES ((SELECT id FROM users WHERE Username = ".$_SESSION['MM_Username']." ), %s, %s)",
GetSQLValueString($_POST['Project_id'], "int"),
GetSQLValueString($_POST['Want'], "text"));

mysql_select_db($database_projectsite, $projectsite);
$Result1 = mysql_query($insertSQL, $projectsite) or die(mysql_error());
}

The student_id comes from the session information that is compared in the table.

The id_project comes from a hidden field that should contain the current id, and the level_of_want comes from the two submit button. When one is selected, that value is applied to the database. Below is how that looks in the form.

<input type="submit" name="Want[]" id="Want_0" value="Really Want" />
      <input type="submit" name="Want[]" id="Want_1" value="Partially Want" />
    </p>
    <p>
      <input name="Project_id" type="hidden" id="Project_id" value="<?php echo $row_Test['Project_id']; ?>" />
    </p>

However when i execute this no information is applied to the database, nor is an error message shown when the button is selected. Does anyone have any possible clue to whats wrong?

Upvotes: 0

Views: 757

Answers (2)

Tomz
Tomz

Reputation: 111

Nathan,

Saw on your submit input is an array

<input type="submit" name="Want[]" id="Want_0" value="Really Want" />
<input type="submit" name="Want[]" id="Want_1" value="Partially Want" />

so to getting value should be 

GetSQLValueString($_POST['Want'][0], "text"));

Tomz

Upvotes: 0

ssj1980
ssj1980

Reputation: 391

I'm guessing because "SELECT id" is returning an empty resultset

try the following:

SELECT id FROM users WHERE Username = '".$_SESSION['MM_Username']."'

Notice the extra single quotes around the double quotes

Upvotes: 2

Related Questions