CODEWITHSUNDEEP
stringbashvariables
howtechstuffworks
howtechstuffworks

Reputation: 1926

Need to split a string in bash after certain number of characters

I am writing a bash script that will execute a command and store the value in a string variable, now I need to split the string after certain characters. Is there a way? I cannot use delimiters coz the format is kinda like this

  PV Name /dev/sda2
  PV Size 10.39 GB

Here I need to get the /dev/sda2 and 10.39 GB(if possible, just 10.39 alone) and write it in a new file. I cannot use delimiter because the space is at first.. I have not done much bash scripting. Is there a way to do this?

Upvotes: 8

Views: 25913

Answers (3)

Facundo Casco
Facundo Casco

Reputation: 10585

You could use cut:

$ echo "PV Name /dev/sda2" |cut -d " " -f 3
/dev/sda2

Upvotes: 3

aland
aland

Reputation: 5189

To get only certain characters, use cut:

 $ echo '1234567' | cut -c2-5
 2345

However, in your case awk looks like better option: 

$ echo '  PV Size 10.39 GB' | awk '{ print $3 }'
10.39

It reads text as space/tab separated columns, so it should work perfectly fine

Upvotes: 9

Dennis Williamson
Dennis Williamson

Reputation: 360143

echo "${var:8}"

will echo the contents of $var starting at the character 8 (zero-based).

To strip off anything starting at the first space:

data=${var:8}
echo "${data%% *}"

Upvotes: 8

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