CODEWITHSUNDEEP
pythonregexstringpython-3.x
user1377384
user1377384

Reputation: 89

Using strip() to clean up a string

I am new to python and I have a string that looks like this

Temp = "', '/1412311.2121\n"

my desired output is just getting the numbers and decimal itself.. so im looking for 

1412311.2121

as the output.. trying to get rid of the ', '/\n in the string.. I have tried Temp.strip("\n") and Temp.rstrip("\n") for trying to remove \n but i still seems to remain in my string. :/... Does anyone have any ideas? Thanks for your help.

Upvotes: 3

Views: 48975

Answers (3)

Joel Cornett
Joel Cornett

Reputation: 24788

Strings are immutable. string.strip() doesn't change string, it's a function that returns a value. You need to do:

Temp = Temp.strip()

Note also that calling strip() without any parameters causes it to remove all whitespace characters, including \n

As stalk said, you can achieve your desired result by calling strip("',/\n") on Temp.

Upvotes: 18

Israel Unterman
Israel Unterman

Reputation: 13510

If the data are like you show, numbers that are wrapped from right and left with non-number data, you can use a very simple regular expression:

g = re.search('[0-9.]+', s)  # capture the inner number only
print g.group(0)

Upvotes: 6

NPE
NPE

Reputation: 500495

I would use a regular expression to do this:

In [8]: s = "', '/1412311.2121\n"

In [9]: re.findall(r'([+-]?\d+(?:\.\d+)?(?:[eE][+-]\d+)?)', s)
Out[9]: ['1412311.2121']

This returns a list of all floating-point numbers found in the string.

Upvotes: 6

Related Questions