Reputation: 159
I am trying to design a slider for my page and I am wondering if anyone knows how to create sliding divs that come from the left to right, and vice versa only when the corresponding button(left & right) is pressed? Can you help?
Here is the code I am trying. I can get the slides to work, but on reaching the ends it still keep sliding right or left continuosly. i want it to stop dynamically once it reaches the ends and on clicking further should alert thru pop up.
can anyone guide me with some example coding
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title> Sample Slide</title>
<style type="text/css">
.total
{
height:350px;
width:75%;
border:1px solid black;
margin-left:auto;
margin-right:auto;
margin-top:15%;
}
.slidepanel
{
border:1px solid purple;
width:100%;
height:100%;
overflow-x: scroll;
overflow-y: hidden;
}
.box-wrapper
{
width: 400%;
height: 90%;
overflow: hidden;
}
.block
{
/* position:absolute;
background-color:#abc;
left:50px;
width:90px;
height:90px;
margin:5px;*/
border:1px solid red;
width:24.9%;
height:98%;
float:left;
margin-left:auto;
margin-right:auto;
position:relative;
left:0px;
}
.block:nth-child(odd) {
background: cyan;
}
.block:nth-child(even) {
background: red;
}
</style>
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript" src="jquery.js"> </script>
<script type="text/javascript">
$(document).ready(function() {
$("#sright").click(function(){
$("#block1,#block2,#block3 ,#block4").animate({"left": "+=24.9%"}, "slow");
});
});
$(document).ready(function() {
$("#sleft").click(function(){
$("#block1,#block2,#block3 ,#block4").animate({"left": "-=24.9%"}, "slow");
});
});
</script>
</head>
<body>
<div class="total">
<div class="slidepanel">
<center><button id="sleft">«</button> <button id="sright">»</button></center>
<div class="box-wrapper">
<div class="block" id ="block1"></div>
<div class="block" id ="block2"></div>
<div class="block" id ="block3"></div>
<div class="block" id ="block4"></div>
</div>
</div>
</div>
</body>
</html>
Upvotes: 2
Views: 7487
Reputation: 498
Try animating in px like this...
Make sure ur all div are available at the time of animation , then try this for one block div
$('#block1').animate({"left": "-=150px"}, 500);
count the no of images available.
on click make sure that max image is not exceeded and u revert back to the first image again, animating back to first image to 0px.
similarly , check for the first image and then when total image width is lesser then total slider width , then do not allow to animate the images to right side.
see if this helps slider tut
Upvotes: 0
Reputation: 34107
[Working Demo][1] : http://jsfiddle.net/XJVYj/ (using your code above)
Hope this helps, This is different from my previous reply of something on the same line: Stop .animate() when it reaches last div
anyhow this demo and code will give you exactly what you looking for.
Rest I will leave the code do the talking;
please note: I have tried to make it simple by using class
attribute instead of chained id
of your div element.
Jquery Code
$(document).ready(function() {
var cur = 1;
var max = $(".box-wrapper div").length;
$("#sright").click(function(){
if (cur == 1 && cur < max)
return false;
cur--;
$(".block").animate({"left": "+=24.9%"}, "slow");
});
$("#sleft").click(function(){
if (cur+1 > max)
return false;
cur++;
$(".block").animate({"left": "-=24.9%"}, "slow");
});
});
Upvotes: 1