CODEWITHSUNDEEP
c#instance-variablesinstances
st4rdog
st4rdog

Reputation: 113

Add variable to array/list without instancing

I'm creating a guitar tab program.

You select notes (GameObject), type a chord name (string), then press a button to add the "Chord" to a list.

The Chord class is just a String and a list of GameObjects. I use currentChord to hold the current selection/name.

When I select a note, I add it to currentChord.selectedList.

When I type a name, I make it currentChord.name.

Chord currentChord;
List<Chord> allChords;

When I click a button, currentChord gets added to allChords (allChords.Add(currentChord)).

The problem is that it's instanced. So when I click to add a different selection/name, the selection of everything in the allChords.notes list changes...

Do I have to use the "new" keyword?

Upvotes: 0

Views: 535

Answers (2)

Josh Peterson
Josh Peterson

Reputation: 2329

You may also want to consider the difference between the struct and class keywords which can be used to define Chord. Using struct will provide value-type behavior, where class will provide reference-type behavior.

For example, this is value-type behavior:

struct Chord
{
    public string Name;
}

...

Chord cMajor = new Chord;
cMajor.Name = "C Major";
Chord cMinor = cMajor; // Make a copy of the Chord instance
cMinor.Name = "C Minor";

Assert.That(cMajor.Name, Is.EqualTo("C Major")); // Assertion succeeds

This is reference-type behavior:

class Chord
{
    public string Name;
}

...

Chord cMajor = new Chord;
cMajor.Name = "C Major";
Chord cMinor = cMajor; // No copy of the Chord instance, just another reference
cMinor.Name = "C Minor";

Assert.That(cMajor.Name, Is.EqualTo("C Major")); // Assertion fails
Assert.That(cMajor.Name, Is.EqualTo("C Minor")); // Assertion succeeds

MSDN provides a nice description: http://msdn.microsoft.com/en-us/library/aa288471(v=vs.71).aspx

Upvotes: 1

Guffa
Guffa

Reputation: 700242

Yes, you have to use the new keyword.

You are adding the same instance to the list over and over, so you end up with a list of references to the same instance.

Create a new instance from the data in currentChord to add to the list, or add the instance in currentChord to the list and then create a new instance and assign to currentChord.

Upvotes: 3

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