CODEWITHSUNDEEP
phpwidgetyii
Barta Tamás
Barta Tamás

Reputation: 899

Yii framework: showdialogbox (CJuiDialog)

I would like to open a dialogbox , but it should be like a part of my menu. I got a CMenu like this: 

<?php $this->widget('zii.widgets.CMenu',array(
            'items'=>array(
                                array('label'=>'Login', 'url'=>"#", 'onclick'=>'$("#mydialog").dialog("open"); return false;'),

                array('label'=>'Logout ('.Yii::app()->user->name.')', 'url'=>array('/site/logout'), 'visible'=>!Yii::app()->user->isGuest),
                                array('label'=>'Home', 'url'=>array('/site/index')),
                                array('label'=>'About Me', 'url'=>array('/site/index'), 
                                    'items'=>array(
                                             array('label'=>'CV', 'url'=>array('/site/cv')),
                                             array('label'=>'Contact', 'url'=>array('/site/contact')))),
                array('label'=>'About', 'url'=>array('/site/page', 'view'=>'about')),



                                array('label'=>'Register', 'url'=>array('/tblUsers/create'))

            ),
        )); ?>

as u can see i already tried to add it somehow to my menu but i have no idea what i am doing. I can open it outside like this :

echo CHtml::link('open dialog', '#', array(
   'onclick'=>'$("#mydialog").dialog("open"); return false;'));

So this is what i actually try to implement in the menu above, with no success.

Upvotes: 1

Views: 1945

Answers (1)

rinat.io
rinat.io

Reputation: 3198

You should use linkOptions or itemOptions for this purpose:

<?php $this->widget('zii.widgets.CMenu',array(
  'items'=>array(
    array('label'=>'Login', 'url'=>"#", 'linkOptions' => array(
       'onclick'=>'$("#mydialog").dialog("open"); return false;'),
    )),
    /* other menu items */
  )
)); ?>

Link to api docs

Upvotes: 4

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