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c++operator-overloadingoverloading
Jason Hu
Jason Hu

Reputation: 1267

C++ overloading operator<<

I'm trying to overload the << operator for a class to emulate toString() in Java. I have a NumExpr class, and has private variable number that I want to output. so here they are:

NumExpr::NumExpr( string n ) {
    number = atoi( n.c_str() );
}
string NumExpr::name() {
    return "num";
}
ostream & operator<<(ostream &s, const NumExpr &num) {
    s << num.number;
    return s;
}

I made it a friend function so it can access the private variable

class NumExpr : public Expr {
    public:
        NumExpr( string v );
        string name();
    private:
        int number;
        friend ostream& operator<<(ostream &s, const NumExpr &num);
};

However I'm getting this error

./ast/Expr.cpp: In function ?std::ostream& operator<<(std::ostream&, const NumExpr&)?: ./ast/Expr.cpp:50: error: no match for ?operator<NumExpr::number? ./ast/Expr.cpp:49: note: candidates are: std::ostream& operator<<(std::ostream&, const NumExpr&)

I have searched for this error, people seem to be having the same problems but mine seems to look like the solutions people are giving out. Is there something fundamentally wrong that I'm doing or is there some syntax shenanigans that I'm not aware of?

Thanks for the help!

Upvotes: 4

Views: 375

Answers (2)

Alok Save
Alok Save

Reputation: 206518

Okay here it is, little bit of playing around I can reproduce your problem:

The problem is that You forgot to include iostream header file.
Add: 

#include<iostream>

and it should just work fine :)

EDIT:
As @James Kanze correctly suggests in comments, it is sufficient to include

#include<istream>

because you don't need everything from the iostream really.
The downside of including iostream inside of istream is little increase in compilation time.

Upvotes: 6

Fantastic Mr Fox
Fantastic Mr Fox

Reputation: 33864

On this page:

http://www.cplusplus.com/forum/beginner/13164/

It says to have the friend function like this:

friend std::ostream& operator<< (std::ostream&, const NumExpr&); <-

so no variable decleration. just 

const NumExpr

any help?

Upvotes: 0

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