CODEWITHSUNDEEP
javaregex
user1422648
user1422648

Reputation: 67

Java regex skipping over matches

I am trying to use Java regular expressions to do something I could have sworn I have done many times over, but it seems I have a problem.

Basically, I am using ".*" to skip over everything I don't need until I find something I need.

It is easier for me to explain in code than in writing:

String str = "class=\"c\" div=34234542234234</span>correct<?> blah=12354234234 </span>wrong<";      
Pattern regex = Pattern.compile("class=\"c\".*</span>([^<]*)");     
Matcher matcher = regex.matcher(str);       
boolean found = false;
while (matcher.find()) {
    found = true;
    System.out.println ("Found match: " + matcher.group(1));            
}       
if (!found)
    System.out.println("No matches found");

Now I want my regex to find the "correct", but instead it skips over to the last match and finds "wrong".

Can anyone help me out?

Upvotes: 2

Views: 445

Answers (1)

Sergey Kalinichenko
Sergey Kalinichenko

Reputation: 726569

You are missing the reluctant qualifier after * - it should be .*? instead.

Upvotes: 2

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