CODEWITHSUNDEEP
iphoneiosnsarray
user1402718
user1402718

Reputation: 45

How is the code for separation of single array into two arrays?

I am getting below response into the nsarray when I used the JSON parsing from my required URL but here I don't like to get 2,1,4,4,6,5,8,7,10,9,12 and 11 in single array I have to get total response into two arrays I mean one array set will consists 2,4,6,8,10 and other array set must be 3,5,7,9 and 11.

So how is the code for separation of single array response into two arrays in iPhone? 

"(\n    2,\n    1\n)",
"(\n    4,\n    3\n)",
"(\n    6,\n    5\n)",
"(\n    8,\n    7\n)",
"(\n    10,\n    9\n)",
"(\n    12,\n    11\n)"

Upvotes: 0

Views: 287

Answers (2)

curtisdf
curtisdf

Reputation: 4210

To split an array, you usually need to loop through all of the values and use an IF ELSE structure to decide which array to put the values in. Also, you need to use NSMutableArray instead of NSArray. Something like this:

NSMutableArray *evenNumbers = [NSMutableArray new];
NSMutableArray *oddNumbers = [NSMutableArray new];
for (NSNumber *value in myArray) {
    if ([value intValue] % 2 == 0) {
        [evenNumbers addObject:value];
    } else {
        [oddNumbers addObject:value];
    }
}

Upvotes: 4

CodaFi
CodaFi

Reputation: 43330

If you combine every number into one large array, you could feasibly test if each number is even or odd with a simple if-else in a for-in loop. Maybe like this:

-(NSArray*)parseJSONIntoArrays:(NSArray*)array {
    NSMutableArray *evenNumbers = [[NSMutableArray alloc]init];
    NSMutableArray *oddNumbers = [[NSMutableArray alloc]init];

    for (NSNumber *number in array) {
        if (([number intValue] %2) == 0) {
            //even
            [evenNumbers addObject:number];
        }
        else {
            //odd
            [oddNumbers addObject:number];
        }
    }
    return [[NSArray alloc]initWithObjects:evenNumbers, oddNumbers, nil];
}

Upvotes: 5

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