CODEWITHSUNDEEP
pythonstringint
bluelantern
bluelantern

Reputation: 1709

Converting list of strings with decimal places to ints in python

example_list = ['21.48678', '21.46552', '21.45145', '21.43822',
                '21.42734', '21.41222', '21.40132', '21.37679']

Im having a bit of trouble converting this list from strings to integers, I would like to also have it as whole numbers. Thanks :)

Upvotes: 1

Views: 8557

Answers (5)

Levon
Levon

Reputation: 143022

[int(round(float(i))) for i in example_list]

will convert items in the list to float, round them and then convert them to int.

Upvotes: 0

NEw usErs...
NEw usErs...

Reputation: 1

new_list=[]
for each in example_list:
    Integer = int(each)
    new_list.append(Integer)
print new_list

This is easy for beginner to understand:D

Upvotes: 0

silijon
silijon

Reputation: 942

foo = ['21.48678', '21.46552', '21.45145', '21.43822', '21.42734', '21.41222', '21.40132', '21.37679']

map(lambda x: int(float(x)), foo)

Upvotes: 2

cval
cval

Reputation: 6819

At first convert to float 

>>> lst = ['21.48678', '21.46552', '21.45145', '21.43822', '21.42734', '21.41222', '21.40132', '21.37679']
>>> ints = [int(float(num)) for num in lst]
[21, 21, 21, 21, 21, 21, 21, 21]

Upvotes: 3

John La Rooy
John La Rooy

Reputation: 304205

Simplest thing is

[int(float(x)) for x in your_list]

This will truncate all the numbers

If you want to round the numbers use this instead

[int(float(x)+.5) for x in your_list]

Upvotes: 7

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