CODEWITHSUNDEEP
javascopeinitializationswitch-statementdeclaration
namalfernandolk
namalfernandolk

Reputation: 9134

Declaring and initializing variables within Java switches

I have a crazy question about Java switches.

int key = 2;

switch (key) {
    case 1:
        int value = 1;
        break;
    case 2:
        value = 2;
        System.out.println(value);
        break;
    default:
        break;
}

Scenario 1 - When the key is two it successfully print the value as 2.
Scenario 2 - When I'm going to comment value = 2 in case 2: it squawks saying the The local variable value may not have been initialized.

Questions :

Scenario 1 : If the execution flow doesn't go to case 1: (when the key = 2), then how does it know the type of the value variable as int?

Scenario 2 : If the compiler knows the type of the value variable as int, then it must have accessed to the int value = 1; expression in case 1:.(Declaration and Initialization). Then why does it sqawrk When I'm going to comment value = 2 in case 2:, saying the The local variable value may not have been initialized.

Upvotes: 112

Views: 30950

Answers (6)

Pavel Molchanov
Pavel Molchanov

Reputation: 2409

Java spec:

https://docs.oracle.com/javase/specs/jls/se12/html/jls-14.html#jls-14.11

The case of abrupt completion because of a break with a label is handled by the general rule for labeled statements (§14.7).

https://docs.oracle.com/javase/specs/jls/se12/html/jls-14.html#jls-14.7

Labeled statements:

LabeledStatement: Identifier : Statement

LabeledStatementNoShortIf: Identifier : StatementNoShortIf

Unlike C and C++, the Java programming language has no goto statement; identifier statement labels are used with break (§14.15) or continue (§14.16) statements appearing anywhere within the labeled statement.

The scope of a label of a labeled statement is the immediately contained Statement.

In other words, case 1, case 2 are labels within the switch statement. break and continue statements can be applied to labels.

Because labels share the scope of the statement, all variables defined within labels share the scope of the switch statement.

Upvotes: 0

Java jansen
Java jansen

Reputation: 197

This Explanation might help.

    int id=1;

    switch(id){
        default: 
            boolean b= false; // all switch scope going down, because there is no scope tag

        case 1:
            b = false;
        case 2:{
            //String b= "test"; you can't declare scope here. because it's in the scope @top
            b=true; // b is still accessible
        }
        case 3:{
            boolean c= true; // case c scope only
            b=true; // case 3 scope is whole switch
        }
        case 4:{
            boolean c= false; // case 4 scope only
        }
    }

Upvotes: 0

Naman
Naman

Reputation: 31868

With the integration of JEP 325: Switch Expressions (Preview) in JDK-12 early access builds. There are certain changes that could be seen from Jon's answer -

  1. Local Variable Scope - The local variables in the switch cases can now be local to the case itself instead of the entire switch block. An example (similar to what Jon had attempted syntactically as well) considering the Day enum class for further explanation :

    public enum Day {
    MONDAY, TUESDAY, WEDNESDAY, THURSDAY, FRIDAY, SATURDAY, SUNDAY
}

// some another method implementation
Day day = Day.valueOf(scanner.next());
switch (day) {
    case MONDAY,TUESDAY -> {
        var temp = "mon-tue";
        System.out.println(temp);
    }
    case WEDNESDAY,THURSDAY -> {
        var temp = Date.from(Instant.now()); // same variable name 'temp'
        System.out.println(temp);
    }
    default ->{
        var temp = 0.04; // different types as well (not mandatory ofcourse)
        System.out.println(temp);
    }
}

  2. Switch Expressions - If the intent is to assign a value to a variable and then make use of it, once can make use of the switch expressions. e.g.

    private static void useSwitchExpression() {
    int key = 2;
    int value = switch (key) {
        case 1 ->  1;
        case 2 -> 2;
        default -> {break 0;}
    };
    System.out.println("value = " + value); // prints 'value = 2'
}

Upvotes: 7

Jon Skeet
Jon Skeet

Reputation: 1500055

Switch statements are odd in terms of scoping, basically. From section 6.3 of the JLS:

The scope of a local variable declaration in a block (§14.4) is the rest of the block in which the declaration appears, starting with its own initializer and including any further declarators to the right in the local variable declaration statement.

In your case, case 2 is in the same block as case 1 and appears after it, even though case 1 will never execute... so the local variable is in scope and available for writing despite you logically never "executing" the declaration. (A declaration isn't really "executable" although initialization is.)

If you comment out the value = 2; assignment, the compiler still knows which variable you're referring to, but you won't have gone through any execution path which assigns it a value, which is why you get an error as you would when you try to read any other not-definitely-assigned local variable.

I would strongly recommend you not to use local variables declared in other cases - it leads to highly confusing code, as you've seen. When I introduce local variables in switch statements (which I try to do rarely - cases should be very short, ideally) I usually prefer to introduce a new scope:

case 1: {
    int value = 1;
    ...
    break;
}
case 2: {
    int value = 2;
    ...
    break;
}

I believe this is clearer.

Upvotes: 122

Paul
Paul

Reputation: 141839

The variable has been declared (as an int), but not initialized (assigned an initial value). Think of the line:

int value = 1;

As:

int value;
value = 1;

The int value part tells the compiler at compile time that you have a variable called value which is an int. The value = 1 part initializes it, but that happens at run-time, and doesn't happen at all if that branch of the switch isn't entered.

Upvotes: 22

Garbage
Garbage

Reputation: 1520

From http://www.coderanch.com/t/447381/java-programmer-SCJP/certification/variable-initialization-within-case-block

Declarations are processed at compile time and do not depend on the execution flow of your code. Since value is declared within the local scope of the switch block, it is useable anywhere in that block from the point of its declaration.

Upvotes: 18

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