CODEWITHSUNDEEP
xmlxpath
gisly
gisly

Reputation: 683

Xpath: select node based in a condition (with local-name())

The question is quite silly, but I am completely stuck. I want to extract child nodes of a node based on a condition. The XML is as follows:

<a> 
 <aCode>aaa</aCode>
 <aValue>bbb</aValue>
</a>

The expression is obvious: //a[aCode='aaa']

But I can't get how I should change it if it is with namespaces and I've got to use local-name(). I've tested the following and it gives a parsing error:

/*[local-name()='a'][[local-name()='aCode']='aaa']

Has anyone any idea of what I should do?

Upvotes: 36

Views: 102704

Answers (3)

karl368
karl368

Reputation: 51

This one work: 

//*[local-name()='a'][*[local-name()='acode' and text()='a2']]

and also this one: 

//*[local-name()='a'][aCode[text()='a2']]

Upvotes: 5

choroba
choroba

Reputation: 241898

You probably meant

//*[local-name()='a'][*[local-name()='aCode']='aaa']

Upvotes: 59

Cylian
Cylian

Reputation: 11182

Try this

/a/aCode[text()='aaa']

or 

//*[local-name() = 'aCode' and text() = 'aaa']

You have used // at wrong place.

Upvotes: 19

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