CODEWITHSUNDEEP
filebatch-filedirectory
psycho
psycho

Reputation: 1611

Check if any type of files exist in a directory using BATCH script

Hello I'm looking to write a batch file to check to see if there are any files of any type inside a given folder.

So far I've tried the following

if EXIST FOLDERNAME\\*.* ( echo Files Exist ) ELSE ( echo "Empty" )

I can get it to work if I know the file extension such as a txt file with the follwing

if EXIST FOLDERNAME\\*.txt ( echo Files Exist ) ELSE ( echo "Empty" )

Thank you for your help

Upvotes: 39

Views: 122243

Answers (4)

Ste
Ste

Reputation: 2293

A roll your own function.

Supports recursion or not with the 2nd switch.

Also, allow names of files with ; which the accepted answer fails to address although a great answer, this will get over that issue.

The idea was taken from https://ss64.com/nt/empty.html

Notes within code.

@echo off
title %~nx0
setlocal EnableDelayedExpansion
set dir=C:\Users\%username%\Desktop
title Echos folders and files in root directory...
call :FOLDER_FILE_CNT dir TRUE
echo !dir!
echo/ & pause & cls
::
:: FOLDER_FILE_CNT function by Ste
::
:: First Written:               2020.01.26
:: Posted on the thread here:   https://stackoverflow.com/q/10813943/8262102
:: Based on:                    https://ss64.com/nt/empty.html
::
:: Notes are that !%~1! will expand to the returned variable.
:: Syntax call: call :FOLDER_FILE_CNT "<path>" <BOOLEAN>
:: "<path>"   = Your path wrapped in quotes.
:: <BOOLEAN>  = Count files in sub directories (TRUE) or not (FALSE).
:: Returns a variable with a value of:
:: FALSE      = if directory doesn't exist.
:: 0-inf      = if there are files within the directory.
::
:FOLDER_FILE_CNT
if "%~1"=="" (
  echo Use this syntax: & echo call :FOLDER_FILE_CNT "<path>" ^<BOOLEAN^> & echo/ & goto :eof
  ) else if not "%~1"=="" (
  set count=0 & set msg= & set dirExists=
  if not exist "!%~1!" (set msg=FALSE)
  if exist "!%~1!" (
   if {%~2}=={TRUE} (
    >nul 2>nul dir /a-d /s "!%~1!\*" && (for /f "delims=;" %%A in ('dir "!%~1!" /a-d /b /s') do (set /a count+=1)) || (set /a count+=0)
    set msg=!count!
    )
   if {%~2}=={FALSE} (
    for /f "delims=;" %%A in ('dir "!%~1!" /a-d /b') do (set /a count+=1)
    set msg=!count!
    )
   )
  )
  set "%~1=!msg!" & goto :eof
  )

Upvotes: 0

Maikel
Maikel

Reputation: 163

For files in a directory, you can use things like:

if exist *.csv echo "csv file found"

or

if not exist *.csv goto nofile

Upvotes: 13

dbenham
dbenham

Reputation: 130859

To check if a folder contains at least one file

>nul 2>nul dir /a-d "folderName\*" && (echo Files exist) || (echo No file found)

To check if a folder or any of its descendents contain at least one file

>nul 2>nul dir /a-d /s "folderName\*" && (echo Files exist) || (echo No file found)

To check if a folder contains at least one file or folder.
Note addition of /a option to enable finding of hidden and system files/folders.

dir /b /a "folderName\*" | >nul findstr "^" && (echo Files and/or Folders exist) || (echo No File or Folder found)

To check if a folder contains at least one folder

dir /b /ad "folderName\*" | >nul findstr "^" && (echo Folders exist) || (echo No folder found)

Upvotes: 57

Bali C
Bali C

Reputation: 31231

You can use this

@echo off
for /F %%i in ('dir /b "c:\test directory\*.*"') do (
   echo Folder is NON empty
   goto :EOF
)
echo Folder is empty or does not exist

Taken from here.

That should do what you need.

Upvotes: 7

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