CODEWITHSUNDEEP
.netnetwork-programming
Matthew
Matthew

Reputation: 923

Detect a 3G internet connection in .NET

Our application downloads data from the internet using RSS but is having connection problems on machines connecting with 3G. We'd like to detect 3G,EDGE,GPRS connections so that we can change the application behaviour, display warnings or status of connection.

How would this be done?

Upvotes: 2

Views: 734

Answers (1)

Noldorin
Noldorin

Reputation: 147310

The NetworkInterface class in the System.Net.NetworkInformation namespace should be of some use to you (more specifically, the GetAllNetworkInterfaces method. An example is shown on the linked MSDN page that demonstrates how to get the type, address, operational status, and other information about every network interface.

Reduced version of MSDN example:

public static void ShowNetworkInterfaces()
{
    IPGlobalProperties computerProperties = IPGlobalProperties.GetIPGlobalProperties();
    NetworkInterface[] nics = NetworkInterface.GetAllNetworkInterfaces();
    Console.WriteLine("Interface information for {0}.{1}     ",
            computerProperties.HostName, computerProperties.DomainName);
    if (nics == null || nics.Length < 1)
    {
        Console.WriteLine("  No network interfaces found.");
        return;
    }

    Console.WriteLine("  Number of interfaces .................... : {0}", nics.Length);
    foreach (NetworkInterface adapter in nics)
    {
        IPInterfaceProperties properties = adapter.GetIPProperties();
        Console.WriteLine();
        Console.WriteLine(adapter.Description);
        Console.WriteLine(String.Empty.PadLeft(adapter.Description.Length,'='));
        Console.WriteLine("  Interface type .......................... : {0}", adapter.NetworkInterfaceType);
        Console.WriteLine("  Physical Address ........................ : {0}", 
                   adapter.GetPhysicalAddress().ToString());
        Console.WriteLine("  Operational status ...................... : {0}", 
            adapter.OperationalStatus);

        Console.WriteLine();
    }
}

Upvotes: 2

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