Reputation: 789
eg. if the Name is: John Deer
the Initials should be: JD
I can use substrings to perform this check on the Initials field, but wondering if I can write a regular expression for it? And is writing a regular expression a better idea than doing it using strings methods?
Upvotes: 14
Views: 25962
Reputation: 172
Simplest version in kotlin
val initials: String = if (str.size > 1) str[0][0].toString() + str[1][0].toString() else str[0][0].toString()
Upvotes: 0
Reputation: 4216
My solution below(C# regex dialect)
^\s*(?>(?<First>\w)\w*).*?((?<Last>\w)\w*)?\s*$
Will match in the named groups First
and Last
the first letter of the first word and the first later of the last word respectively, happy ignoring all the words that may be in between and not caring if there are trailing or leading spaces
No replace are needed, the match occurs in one line and you can extract the letter accessing the matching group by name like this
var displayName = "Nick 'Goose' Bradshaw";
var initialsRule = new Regex(@"^\s*(?>(?<First>\w)\w*).*?((?<Last>\w)\w*)?\s*$");
var matches = initialsRule.Match(displayName);
var initials = $"{matches.Groups["First"].Value}{matches.Groups["Last"].Value}";
//initials: "NB"
Upvotes: 0
Reputation: 39404
Here's an alternative with an emphasis on keeping it simple:
/// <summary>
/// Get initials from the supplied names string.
/// </summary>
/// <param name="names">Names separated by whitespace</param>
/// <param name="separator">Separator between initials (e.g "", "." or ". ")</param>
/// <returns>Upper case initials (with separators in between)</returns>
public static string GetInitials(string names, string separator)
{
// Extract the first character out of each block of non-whitespace
Regex extractInitials = new Regex(@"\s*([^\s])[^\s]*\s*");
return extractInitials.Replace(names, "$1" + separator).ToUpper();
}
There is a question of what to do if the supplied names aren't as expected. Personally I think it should just return the first character from each chunk of text that isn't whitespace. E.g:
1Steve 2Chambers => 12
harold mcDonald => HM
David O'Leary => DO
David O' Leary => DOL
Ronnie "the rocket" O'Sullivan => R"RO
There will be those who'd argue for more sophisticated/complex techniques (e.g. to handle the last one better) but IMO this is really a data cleansing issue.
Upvotes: 2
Reputation: 375
This is my approach:
public static string GetInitials(string names) {
// Extract the first character out of each block of non-whitespace
// exept name suffixes, e.g. Jr., III. The number of initials is not limited.
return Regex.Replace(names, @"(?i)(?:^|\s|-)+([^\s-])[^\s-]*(?:(?:\s+)(?:the\s+)?(?:jr|sr|II|2nd|III|3rd|IV|4th)\.?$)?", "$1").ToUpper();
}
Handled cases:
// Mason Zhwiti -> MZ
// mason zhwiti -> MZ
// Mason G Zhwiti -> MGZ
// Mason G. Zhwiti -> MGZ
// John Queue Public -> JQP
// John-Queue Public -> JQP
// John Q. Public, Jr. -> JQP
// John Q Public Jr. -> JQP
// John Q Public Jr -> JQP
// John Q Public Jraroslav -> JQPJ
// Thurston Howell III -> TH
// Thurston Howell, III -> TH
// Thurston Howell the III -> TH
// Malcolm X -> MX
// A Ron -> AR
// A A Ron -> AAR
// Madonna -> M
// Chris O'Donnell -> CO
// Chris O' Donnell -> COD
// Malcolm McDowell -> MM
// Éric Ígor -> ÉÍ
// 행운의 복숭아 -> 행복
Not handled cases:
// James Henry George Michael III the second -> JHGMIts
// Robert "Rocky" Balboa, Sr. -> R"B
// 1Bobby 2Tables -> 12 (is it a real name?)
Upvotes: 9
Reputation: 6540
Here is my solution. My goal was not to provide the simplest solution, but one that can take a variety of (sometimes weird) name formats, and generate the best guess at a first and last name initial (or in the case of mononymous people) a single initial.
I also tried to write it in a way that is relatively international-friendly, with unicode regexes, although I don't have any experience in generating initials for many kinds of foreign names (e.g. Chinese), though it should at least generate something usable to represent the person, in under two characters. For example, feeding it a name in Korean like "행운의 복숭아" will yield 행복 as you might have expected (although perhaps that is not right way to do it in Korean culture).
/// <summary>
/// Given a person's first and last name, we'll make our best guess to extract up to two initials, hopefully
/// representing their first and last name, skipping any middle initials, Jr/Sr/III suffixes, etc. The letters
/// will be returned together in ALL CAPS, e.g. "TW".
///
/// The way it parses names for many common styles:
///
/// Mason Zhwiti -> MZ
/// mason lowercase zhwiti -> MZ
/// Mason G Zhwiti -> MZ
/// Mason G. Zhwiti -> MZ
/// John Queue Public -> JP
/// John Q. Public, Jr. -> JP
/// John Q Public Jr. -> JP
/// Thurston Howell III -> TH
/// Thurston Howell, III -> TH
/// Malcolm X -> MX
/// A Ron -> AR
/// A A Ron -> AR
/// Madonna -> M
/// Chris O'Donnell -> CO
/// Malcolm McDowell -> MM
/// Robert "Rocky" Balboa, Sr. -> RB
/// 1Bobby 2Tables -> BT
/// Éric Ígor -> ÉÍ
/// 행운의 복숭아 -> 행복
///
/// </summary>
/// <param name="name">The full name of a person.</param>
/// <returns>One to two uppercase initials, without punctuation.</returns>
public static string ExtractInitialsFromName(string name)
{
// first remove all: punctuation, separator chars, control chars, and numbers (unicode style regexes)
string initials = Regex.Replace(name, @"[\p{P}\p{S}\p{C}\p{N}]+", "");
// Replacing all possible whitespace/separator characters (unicode style), with a single, regular ascii space.
initials = Regex.Replace(initials, @"\p{Z}+", " ");
// Remove all Sr, Jr, I, II, III, IV, V, VI, VII, VIII, IX at the end of names
initials = Regex.Replace(initials.Trim(), @"\s+(?:[JS]R|I{1,3}|I[VX]|VI{0,3})$", "", RegexOptions.IgnoreCase);
// Extract up to 2 initials from the remaining cleaned name.
initials = Regex.Replace(initials, @"^(\p{L})[^\s]*(?:\s+(?:\p{L}+\s+(?=\p{L}))?(?:(\p{L})\p{L}*)?)?$", "$1$2").Trim();
if (initials.Length > 2)
{
// Worst case scenario, everything failed, just grab the first two letters of what we have left.
initials = initials.Substring(0, 2);
}
return initials.ToUpperInvariant();
}
Upvotes: 25
Reputation: 3355
[a-z]+[a-z]+\b
which will net you The first two letters of each name...
where name = 'Greg Henry' = 'G H' or 'James Smith' 'J S'
Then you can split on ' ' and join on ''
This even works on names like
'James Henry George Michael' = 'J H G M'
'James Henry George Michael III the second' = 'J H G M III'
If you want to avoid the split utilize [a-z]+[a-z]+\b ?
But then names like Jon Michael Jr. The 3rd
will be = JMJr.T3
where as the above option allows you to get 'The', 'the' and '3rd' if you wanted ..
If you really wanted to be fancy you could use the (\b[a-zA-Z])[a-zA-Z]* ?
to match just the parts of the name and then replace with the former.
Upvotes: 0
Reputation: 2683
Personally, I prefer this Regex
Regex initials = new Regex(@"(\b[a-zA-Z])[a-zA-Z]* ?");
string init = initials.Replace(nameString, "$1");
//Init = "JD"
That takes care of initials, and whitespace removal (thats the ' ?' at the end there).
The only thing you have to worry about are titles and puctuation like Jr. or Sr., or Mrs....etc etc. Some people do include those in their full names
Upvotes: 23
Reputation: 3125
How about this:
string name = "John Clark MacDonald";
var parts = name.Split(' ');
string initials = "";
foreach (var part in parts)
{
initials += Regex.Match(part, "[A-Z]");
Console.WriteLine(part + " --> " + Regex.Match(part,"[A-Z]"));
}
Console.WriteLine("Final initials: " + initials);
Console.ReadKey();
This allows for optional middle names, and works for multiple capitalizations, as shown above.
Upvotes: 0
Reputation: 1155
Yes, use a regex. You can use the Regex.Match and Regex.Match.Groups methods to find matches and then to extract the matching values you need - the initials in this case. Finding and extracting values will happen at the same time.
Upvotes: 0
Reputation: 7282
How about this?
var initials = Regex.Replace( "John Deer", "[^A-Z]", "" );
Upvotes: 2
Reputation: 13579
try this one
(^| )([^ ])([^ ])*','\2')
or this one
public static string ToInitials(this string str)
{
return Regex.Replace(str, @"^(?'b'\w)\w*,\s*(?'a'\w)\w*$|^(?'a'\w)\w*\s*(?'b'\w)\w*$", "${a}${b}", RegexOptions.Singleline)
}
Upvotes: 0