Reputation:
For some reason in my where it says that "firstname" does not exist in the Opportunity Entity. But it is set for the SystemUser Entity. Any idea why it is getting confused? Thanks!
var linqQuery = (from r in gServiceContext.CreateQuery("opportunity")
join c in gServiceContext.CreateQuery("account") on ((EntityReference)r["accountid"]).Id equals c["accountid"]
join u in gServiceContext.CreateQuery("systemuser") on ((EntityReference)r["ownerid"]).Id equals u["systemuserid"]
where r["new_leadstatus"].Equals("100000004") && u["lastname"].Equals(rsmLastName) && u["firstname"].Equals(rsmFirstName)
select new
{
AccountId = !r.Contains("accountid") ? string.Empty : r["accountid"],
Account = !r.Contains("name") ? string.Empty : r["name"]
});
Upvotes: 8
Views: 951
Reputation: 5362
Make sure you put each where
clause in its own line per Microsoft guidelines.
The where clause applies a filter to the results, often using a Boolean expression. The filter specifies which elements to exclude from the source sequence. Each where clause can only contain conditions against a single entity type. A composite condition involving multiple entities is not valid. Instead, each entity should be filtered in separate where clauses.
var linqQuery = from r in gServiceContext.CreateQuery("opportunity")
join c in gServiceContext.CreateQuery("account") on ((EntityReference)r["accountid"]).Id equals c["accountid"]
join u in gServiceContext.CreateQuery("systemuser") on ((EntityReference)r["ownerid"]).Id equals u["systemuserid"]
where r["new_leadstatus"].Equals("100000004")
where u["lastname"].Equals(rsmLastName) && u["firstname"].Equals(rsmFirstName)
select new
{
AccountId = !r.Contains("accountid") ? string.Empty : r["accountid"],
Account = !r.Contains("name") ? string.Empty : r["name"]
};
Upvotes: 11
Reputation: 12571
You define your reference to the Opportunity entity as 'r' but are trying to read firstname from 'u'
from r in gServiceContext.CreateQuery("opportunity")
u["firstname"]
Change the end of your where to
r["firstname"].Equals(rsmFirstName)
Upvotes: 2