Reputation: 499
I am trying to contruct a regular expression to remove links from content unless it contains 1 of 2 conditions.
<a.*?href=[""'](http[s]?:\/\/(.*?)\.link\.com)?\/(?!m\/).*?<\/a>
This will match any link to link.com that does not have m/ at the end of the domain section. I want to change this slightly so it does't match URLs that are links to pdf files regardless of having the m/ in the url, I came up with:
<a.*?href=["'](http[s]?:\/\/(.*?)\.brodies\.com)?\/(?!m\/).*?\.(?!pdf)["'].*?<\/a>
Which is ooh so very close except now it will only match if the URL has a "." at the end - I can see why it's doing it. I can't seem to make the "." optional as this causes the non greedy pattern prior to the "." to keep going until it hits the ["']
Any help would be good to help solve this.
Thanks Paul
Upvotes: 0
Views: 68
Reputation: 30273
First, RegEx match open tags except XHTML self-contained tags.
That said, (since it probably will not deter,) here is a slightly-better-constrained version of what you're trying to, with the caveat that this is still not good enough!
<a[^>]+?href\s*=\s*["'](https?:\/\/[^"']*?\.link\.com)?\/(?!m\/)[^"']*?\.(?!pdf)[^"']*?["'][^>]*?>.*?<\/a>
You can see a running example of this regex at: http://rubular.com/r/obkKrKpB8B.
Your problem was actually just that you were looking for a quote character immediately after the dot, here: .(?!pdf)["']
.
Upvotes: 1
Reputation: 33908
You probably want to use (?<!\.pdf)["']
instead of \.(?!pdf)["']
.
But note that this expression has several issues, best way to solve them is to use a proper HTML parser.
Upvotes: 1