AWK multiple conditionals not printing

Question

I'm looking for zoom to understand why this:

palabra=s_gonzalez
i=10
awk -vvar1=$palabra -vvvar2=$i '( $1 == var1 ) && ( $2 == var2 ) {print $0}' As

is not printing anything. The As file contains:

r_castillo  10
flores  6
s_gonzalez  10
o_gutzwiller    12
h_ji    4

Thanks in advance for any suggestion.

Answer 1

As a technique to avoid this sort of problem, you can assign variables without -v. I would rewrite the command:

awk '$1==var1 && $2==var2' var1=$palabra var2=$i As

It always seems simpler to me to assign variables as arguments after the program rather than as -v options before the program. (-v assignments are available in the BEGIN block, but that is irrelevant in this case.)

Answer 2

Where're your:

vvar2

Did you misspell var2?