Reputation: 663
As the title says I am unable to find the control I want.
This is the GridView:
<asp:GridView ID="gvInfo" runat="server" AutoGenerateColumns="false" AutoGenerateEditButton="true">
<Columns>
<asp:BoundField DataField="filename" HeaderText="Filename" SortExpression="filename" />
<asp:ButtonField ButtonType="Button" CommandName="Select"
HeaderText="Move File" ShowHeader="True" Text="Move File" />
</Columns>
</asp:GridView>
This is the code behind:
Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
If Not IsPostBack Then
ShowGV()
End If
End Sub
Protected Sub gvInfo_RowEditing(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.GridViewEditEventArgs) Handles gvInfo.RowEditing
gvInfo.EditIndex = e.NewEditIndex
ShowGV()
End Sub
Protected Sub gvInfo_RowCancelingEdit(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.GridViewCancelEditEventArgs) Handles gvInfo.RowCancelingEdit
gvInfo.EditIndex = -1
ShowGV()
End Sub
Protected Sub gvInfo_RowUpdating(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.GridViewUpdateEventArgs) Handles gvInfo.RowUpdating
Dim row = gvInfo.Rows(e.RowIndex)
Dim Test As String = CType(row.FindControl("filename"), TextBox).Text
Response.Write(Test)
gvInfo.EditIndex = -1
ShowGV()
End Sub
Any help is much appreciated.
Thanks.
Upvotes: 2
Views: 6573
Reputation: 11464
Try
CType(row.Cells(0).Controls(0), TextBox).Text
'change index of `cell(0)` to required column index (column index starts from 0)
or
convert required column to a TemplateField
and use,
CType(row.FindControl("LabelNamein'EditItemTemplate'"), TextBox).Text
Upvotes: 2