Cripto
Cripto

Reputation: 3751

Refreshing or opening page inserts empty data into my database! PHP, From

I have a form with several input. However, when I just simply load the page, a blank item gets added to the database. Even when I enter the site for the first time, cleared cookies and all, it still adds empty data to the db Why is that?

<body>





<hr></hr>
<div
style="

margin-left:auto;
margin-right:auto;

width:600px;
"
>
<form method="post" action="admin.php" name="main" id="main">
Post to:
<select name="wheretopost" onchange="testValue(this);" name="select" id="select">
<option value="blog">Blog</option>
<option name='links' value="links">Links</option>
<option value="apparel">Apparel</option>
<option value="goods">Goods</option>
</select>
<div class="productKind" style="padding:10px;">
Mens<input type="radio" name="productKind" id="productKind"  value="Mens">
Womens<input type="radio" name="productKind" id="productKind"  value="Womens">
Kids<input type="radio" name="productKind" id="productKind"  value="Kids">
</div>
<div class="goodsKind" style="padding:10px;">
Stickers<input type="radio" name="goodsKind" id="goodsKind"  value="Stickers">
Incense<input type="radio" name="goodsKind" id="goodsKind"  value="Incense">
Patches<input type="radio" name="goodsKind" id="goodsKind"  value="Patches">
</div>
<br/>
Subject:<br/>
<input type="text" name="title" style="width:100%;" />
<br/>
<br/>
TextArea:<br/>
 <textarea name="txtarea" style="width:100%;" rows="30">
 </textarea>

<center> <input type="submit" style="width:300px;" />
</center>
</form>

</div>






<?php
$type = $_POST["wheretopost"];
$title = $_POST["title"];
$body = $_POST["txtarea"];
$date = date("F j, Y");
?>


<?
$sql = "INSERT INTO `yoyo`.`posts` (`id`, `type`, `title`, `body`, `date`) VALUES (NULL, '$type', '$title', '$body', '$date');";
mysql_query($sql);

?>


 </body>
</html>

note that the page it posts to is its self. (could that be the problem?)

Upvotes: 0

Views: 6673

Answers (6)

user214393
user214393

Reputation: 11

This method work for I put everything into single condition:

if (!$conn)
{
  die('Could not connect: ' . mysql_error());

$sql = "INSERT INTO emp_info
       (user_nam,f_fnam,l_nam,ref_id,web,comp,str,city,coun)
       VALUES ('$myvar','$myvar1','$myvar2','$myvar3','$myvar4','$myvar5','$myvar6','$myvar7','$myvar8')";
       //echo  $sql; 
      //echo $html;
      mysqli_close($conn);  }
?>

Upvotes: 0

Zuber Surya
Zuber Surya

Reputation: 869

i hope this is the solution of your problem

<?php 
if(isset($_POST['submit']))
{
 //     write you php code for insert here
}else{ ?>
//       all your html form contents
 <?php } ?>

thats it...

Upvotes: 1

baptme
baptme

Reputation: 10092

Simply use if(isset(...

<?php
if(isset($_POST["wheretopost"]){
$type = $_POST["wheretopost"];
$title = $_POST["title"];
$body = $_POST["txtarea"];
$date = date("F j, Y");
$sql = "INSERT INTO `yoyo`.`posts` (`id`, `type`, `title`, `body`, `date`) VALUES (NULL, '$type', '$title', '$body', '$date');";
mysql_query($sql);
}
?>

Upvotes: 0

user1299518
user1299518

Reputation:

perhaps because your php code is JUST called at the end of your .php?

<?php
$type = $_POST["wheretopost"];
...

just take this php code and wrap it between an IF condition, like:

if (isset($_POST)) {
   .. code
}

more over, you can write a specific IF condition, checking just an input before proceeding, like (place it inside your form): <input type="hidden" name="postit" value="1" />

if (isset($_POST) && isset($_POST["postit"]) && $_POST["postit"]==1) {
   .. code
}

Upvotes: 0

falinsky
falinsky

Reputation: 7428

Every time you load a page, you execute next script:

<?php
$type = $_POST["wheretopost"];
$title = $_POST["title"];
$body = $_POST["txtarea"];
$date = date("F j, Y");
?>


<?
$sql = "INSERT INTO `yoyo`.`posts` (`id`, `type`, `title`, `body`, `date`) VALUES (NULL, '$type', '$title', '$body', '$date');";
mysql_query($sql);

?>

Even if you post nothing to it, you get empty results from $_POST array and so add to the database empty records.

Upvotes: 0

ok32
ok32

Reputation: 1321

Check that request is post before inserting something:

if ($_SERVER['REQUEST_METHOD'] == 'POST') {
    $type = $_POST["wheretopost"];
    $title = $_POST["title"];
    $body = $_POST["txtarea"];
    $date = date("F j, Y");

    $sql = "INSERT INTO `yoyo`.`posts` (`id`, `type`, `title`, `body`, `date`) VALUES (NULL, '$type', '$title', '$body', '$date');";
    mysql_query($sql);
}

Upvotes: 5

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