CODEWITHSUNDEEP
wolfram-mathematicacurve
ZelelB
ZelelB

Reputation: 2010

Catenary with Manipulate

I would like to represent a Catenary-curve in Mathematica, and then allow the user to Manipulate each of the parameters, like the Hanging-Points' position (A,B), the cable's weight, the force of gravity etc.?

Upvotes: 2

Views: 920

Answers (1)

Niki
Niki

Reputation: 15867

I would do it like this:

First, define the catenary:

catenary[x_] := a*Cosh[(x - c)/a] + y

Now I can either find the parameters a, c and y of this curve numerically, using FindRoot:

Manipulate[
 Module[{root},
  (
   root = FindRoot[
             {
                catenary[x1] == y1, 
                catenary[x2] == y2
             } /. {x1 -> pt[[1, 1]], y1 -> pt[[1, 2]], x2 -> pt[[2, 1]], y2 -> pt[[2, 2]], a -> \[Alpha]}, 
             {{y, 0}, {c, 0}}];
   Show[
    Plot[catenary[x] /. root /. a -> \[Alpha], {x, -2, 2}, 
     PlotRange -> {-3, 3}, AspectRatio -> 3/2],
    Graphics[{Red, Point[pt]}]]
   )], {{\[Alpha], 1}, 0.001, 10}, {{pt, {{-1, 1}, {1, 1}}}, Locator}]

Alternatively, you could solve for the parameters exactly:

solution = Simplify[Solve[{catenary[x1] == y1, catenary[x2] == y2}, {y, c}]]

and then use this solution in the Manipulate:

Manipulate[
 (
  s = (solution /. {x1 -> pt[[1, 1]], y1 -> pt[[1, 2]], 
      x2 -> pt[[2, 1]], y2 -> pt[[2, 2]], a -> \[Alpha]});
  s = Select[s, 
    Im[c /. #] == 0 && 
      Abs[pt[[1, 2]] - catenary[pt[[1, 1]]] /. # /. a -> \[Alpha]] < 
       10^-3 &];
  Show[
   Plot[catenary[x] /. s /. a -> \[Alpha], {x, -2, 2}, 
    PlotRange -> {-3, 3}, AspectRatio -> 3/2],
   Graphics[{Red, Point[pt]}]]
  ), {{\[Alpha], 1}, 0.001, 10}, {{pt, {{-1., 1.}, {1., 0.5}}}, 
  Locator}]

The FindRoot version is faster and more stable, though. Result looks like this:

enter image description here

For completeness' sake: It's also possible to find a catenary through 3 points:

m = Manipulate[
  Module[{root},
   (
    root = 
     FindRoot[
      catenary[#[[1]]] == #[[2]] & /@ pt, {{y, 0}, {c, 0}, {a, 1}}];
    Show[
     Plot[catenary[x] /. root, {x, -2, 2}, PlotRange -> {-3, 3}, 
      AspectRatio -> 3/2],
     Graphics[{Red, Point[pt]}]]
    )], {{pt, {{-1, 1}, {1, 1}, {0, 0}}}, Locator}]

enter image description here

Upvotes: 4

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