CODEWITHSUNDEEP
java
Karlovsky120
Karlovsky120

Reputation: 6352

Java speed and memory occupation "contest"

I have a general question about Java.

What is better?

case 1:

a = method1(7);
b = method2(a);
c = method3(b);

or

c = method3(method2(method1(7)));

case 2:

String a = method1(1);
String b = method2(2);
String c = method3(3);
String d = a+b+c;

or

String d = method1(1)+method2(2)+method3(3);

I was wondering what would be better speed-wise... I guess the second way (on both) is better memory occupation-wise, but I always wondered if one was faster than the other or if they take same amount of time to execute. I'm making a program that calls the same function many times, so every milisecond counts!

If there is another category in which they can compete (except speed, etc.), tell me too!

Upvotes: 3

Views: 69

Answers (1)

Sergey Kalinichenko
Sergey Kalinichenko

Reputation: 726479

There will be no discernable difference in the execution speed. The only distinction between the code that uses temporary variables for intermediate results is that you'd be able to see intermediate values in the debugger. Moreover, if the values of intermediate variables are not used after the call to the target function, good chances are that the compiler will optimize these variables out, producing an identical byte code.

Upvotes: 4

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