Reputation: 2830
I'm using Maven 3.0.3 and Java 6. I want to put a WSDL URL property somewhere that both the Maven build process can acccess and my runtime Java code (I'm building a Maven JAR project) can also access. How would I structure/configure this? In my runtime Java code, I have something like
String wsdlUrl = getProperty("wsdl.url");
and in Maven, I want to access the WSDL URL in a plugin like so ...
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>jaxws-maven-plugin</artifactId>
<executions>
<execution>
<goals>
<goal>wsimport</goal>
</goals>
<configuration>
<wsdlUrls>
<wsdlUrl>${wsdl.url}</wsdlUrl>
</wsdlUrls>
<sourceDestDir>${basedir}/src/main/java</sourceDestDir>
<packageName>org.myco.bsorg</packageName>
</configuration>
</execution>
</executions>
</plugin>
Upvotes: 4
Views: 4835
Reputation: 48045
You should be using maven resource filtering to accomplish that.
Here is an example that will work for you.
layout
+- pom.xml
+- src
+- main
+- java
+- resources
+- application.properties
pom.xml
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.company</groupId>
<artifactId>application</artifactId>
<version>1.0.0-SNAPSHOT</version>
<name>${project.artifactId}-${project.version}</name>
<properties>
<wsdl.url>http://some.url</wsdl.url>
</properties>
<build>
<plugins>
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>jaxws-maven-plugin</artifactId>
<executions>
<execution>
<goals>
<goal>wsimport</goal>
</goals>
<configuration>
<wsdlUrls>
<wsdlUrl>${wsdl.url}</wsdlUrl>
</wsdlUrls>
<sourceDestDir>${basedir}/src/main/java</sourceDestDir>
<packageName>org.myco.bsorg</packageName>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
<resources>
<resource>
<directory>src/main/resources</directory>
<filtering>true</filtering>
</resource>
</resources>
</build>
</project>
src/main/resources/application.properties
wsdl.url = ${wsdl.url}
Then in your code you can load the properties file and get the property wsdl.url
.
src/main/java/com/company/Main.java
package com.company;
import java.io.IOException;
import java.io.InputStream;
import java.util.Properties;
/**
* @author maba, 2012-06-04
*/
public class Main {
public static void main(String[] args) throws IOException {
ClassLoader loader = Main.class.getClassLoader();
InputStream in = loader.getResourceAsStream("application.properties");
Properties properties = new Properties();
properties.load(in);
String url = (String) properties.get("wsdl.url");
System.out.println(url);
}
}
Upvotes: 2
Reputation: 15699
Create a .properties
file inside the src/main/resources
directory.
Use a properties-maven-plugin and load properties from this file, like this (after the usage site):
<project>
<build>
<plugins>
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>properties-maven-plugin</artifactId>
<version>1.0-alpha-2</version>
<executions>
<execution>
<phase>initialize</phase>
<goals>
<goal>read-project-properties</goal>
</goals>
<configuration>
<files>
<file>src/main/resources/common.properties</file>
</files>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
Use Properties#load(InputStream) and load properties like this:
String propertiesFileName = "/common.properties";
Properties properties = new Properties();
InputStream inputStream = this.getClass().getClassLoader()
.getResourceAsStream(propertiesFileName);
properties.load(inputStream);
Upvotes: 5
Reputation: 37506
src/main/resources or src/test/resources is accessible to maven and will be automatically massaged into the jar at build time.
Upvotes: 0